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4 years ago

(2x^3-5x^2+8)(x+3)=?

1 answer:

8 0

(2x³ - 5x² + 8)(x + 3) = ?
First step is to distribute.

2x^4 + 6x³ - 5x³ - 15x² + 8x + 24
Now combine like terms.

2x^4 + x³ - 15x² + 8x + 24

This is your answer, since you can't simplify any further or solve it without some more information.

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It's an overcast day in Hayward and you're waiting for AC Transit 97 Bus Line to show up. Your weather app says there's a 30% ch

melomori [17]

Answer:

$P(r n L) = 0.12$

$P(L) = 0.225$

$P(\= r | L) = 0.4667$

Step-by-step explanation:

The chance that it will rain is $P(r ) = 0.30$

The chance that it does not rain is $P(\= r ) = 1 - P(r )$

$P(\= r ) = 1 -0.30$

$P(\= r ) = 0.70$

The probability that the bus run late if it rains is $P(L | r) = 0.4$

The probability that the bus run late if it does not rain is $P(L | \= r) = 0.15$

Generally the probability that it will rain and the bus will be late is mathematically represented as

$P(r n L) = P(L | r) * P(r)$

=> $P(r n L) = 0.4 * 0.30$

=> $P(r n L) = 0.12$

Generally the probability that the bus will be late is mathematically represented as

$P(L) = P(r) * P(L|r) + P(L | \= r) * P(\= r)$

=> $P(L) = 0.30 * 0.4 +0.15*0.70$

=> $P(L) = 0.225$

Generally given that the bus ran late, the probability that the bus it was not raining is mathematically represented as

$P(\= r | L) = 1- P(r | L )$

Here $P(r | L ) = \frac{P(r n L)}{P(L)}$

=> $P(r | L ) = \frac{0.12}{0.225}$

=> $P(r | L ) = 0.533$

$P(\= r | L) = 1- 0.533$

=> $P(\= r | L) = 0.467$

3 0

3 years ago

Roberta wants to create 17 ounces of new hand lotion, with a minimum 15% concentration of beeswax, from a mixture of two lotions

Zarrin [17]

Answer:

Step-by-step explanation:

Given the inequality

0.21x + 0.05(17 - x) > 2.55 where x is the amount of 21% lotion needed

Given

0.21x + 0.05(17 - x) > 2.55

Open the parenthesis

0.21x + 0.85-0.05x > 2.55

Collect like terms

0.21x-0.05x+0.85>2.55

0.16x+0.85>2.55

0.16x>2.55-0.85

0.16x > 1.7

x > 1.7/0.16

x > 10.625

Hence she will need 21% lotion approximately greater than 10 ounces

6 0

4 years ago

Find the inverse please and thank you

Amanda [17]

The inverse $f^{-1}(x)$ is such that

$f\left(f^{-1}(x)\right) = x$

We have

$f\left(f^{-1}(x)\right) = -9\sqrt{f^{-1}(x) - 8} + 5 = x$

Solve for the inverse.

$-9\sqrt{f^{-1}(x)-8} + 5 = x \\\\ -9\sqrt{f^{-1}(x)-8} = x-5 \\\\ \sqrt{f^{-1}(x)-8} = -\dfrac{x-5}9 \\\\ \left(\sqrt{f^{-1}(x)-8}\right)^2 = \left(-\dfrac{x-5}9\right)^2 \\\\ f^{-1}(x) - 8 = \dfrac{(x-5)^2}{81} \\\\ \boxed{f^{-1}(x) = 8 + \dfrac{(x-5)^2}{81}}$