The minimum number of cards which must be drawn to get atleast 3 cards of aces is 4.
According to the given question.
We have a deck of cards.
As, we know that
The total numbers of cards in a deck = 52
Since, we have to find the minimum number of cards to be drawn so that we will get atleast 3 cards of aces.
As they have used atleast in the question so the cards can be more also so we have to reach at minimum number of cards to be drawn to guarantee atleast 3 cards of aces.
Number of suits in a standard deck= 4 (Clubs, Hearts, Diamond, Spades)
Number of aces in a suit = 1
We need atleast three cards of aces. Which means that we have 4*1 =4 cards from each suit.
Thereofre, the minimum number of cards which must be drawn to get atleast 3 cards of aces is 4.
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Answer:
z=−215z=-215
Step-by-step explanation:
z=−215z=-215
Answer:
No, binomial distribution cannot be applied.
Step-by-step explanation:
We known that a Binomial Distribution depends on provided experiment , a binomial distribution have only 2 outcomes. For example, when we flip a coin in the air, then the possible outcomes are Head and Tail.
But in the context, an American roulette wheel has outcomes. It means when we spin the American Roulette wheel, ball may lend on any of the numbers between 0 to 36. So there are more than outcomes.
Therefore, binomial distribution can not be applied here.
4x+ 3y = 29
2x - 3y = 1
6x = 30
6 6
x = 5
4x + 3y = 29
4(5) + 3y = 29
20 + 3y = 29
- 20 - 20
3y = 9
3 3
y = 3
(x, y) = (5, 3)
Answer: Ricky: 0 Pedro: 281
Explanation: The question says that Pedro AND Ricky got 281 base hits. Meaning that’s the total number of hits for both Ricky and Pedro. So if the total hits are 281 and Pedro has 281 hits more than Ricky. Ricky can only have 0 hits.