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zhuklara [117]
3 years ago
9

If f(x) = x3+ x2and g(x) = x4+ x2+ x, what is the value of f(x) –g(x) when x = 1?

Mathematics
1 answer:
Serggg [28]3 years ago
8 0

Answer:

<h2>B) -1</h2>

Step-by-step explanation:

f(x)=x^3+x^2\\\\g(x)=x^4+x^2+x

<h3>METHOD 1</h3>

f(x)-g(x)=(x^3+x^2)-(x^4+x^2+x)=x^3+x^2-x^4-x^2-x\\\\=-x^4+x^3-x\\\\x=1\\\\-1^4+1^3-1=-1+1-1=-1

<h3>METHOD 2</h3>

x=1\\\\f(1)=1^3+1^2=1+1=2\\\\g(1)=1^4+1^2+1=1+1+1=3\\\\f(1)-g(1)=2-3=-1

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Answer:

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Step-by-step explanation:

Antiderivative F(x)

This is the integral of F^{\prime}(x)

So

F′(x) = f(x) = 6 + 24x^3 + 18x^5

Then:

F(x) = \int (6 + 24x^3 + 18x^5) dx

F(x) = 6x + \frac{24x^4}{4} + \frac{18x^6}{6} + K

F(x) = 6x + 6x^4 + 3x^6 + K

F(1)=0

F(X) = 0 when x = 1. We use this to find K.

F(x) = 6x + 6x^4 + 3x^6 + K

0 = 6 + 6 + 3 + K

K = -15

Thus

The antiderivative is F(X) = 6x + 6x^4 + 3x^6 - 15.

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