divisions between $389$ and $390$ so each division is $\frac{390-389}{10}=0.1$
A is 8 division from $389$, so, A is $389+8\times 0.1=389.8$
similarly, C is one division behind $389$ so it is $389-1\times 0.1=388.9$
and B is $390.3$
Answer: 4p^2-2p
Step-by-step explanation:
Answer:
5 seed packets
Step-by-step explanation:
65 divided by 13 is 5
Answer:
work is shown and pictured
Answer:answer is a (x+8)^2=86
Step-by-step explanation:
x+8=±√
86
2 Break down the problem into these 2 equations.
x+8=\sqrt{86}x+8=√
86
x+8=-\sqrt{86}x+8=−√
86
3 Solve the 1st equation: x+8=\sqrt{86}x+8=√
86
.
x=\sqrt{86}-8x=√
86
−8
4 Solve the 2nd equation: x+8=-\sqrt{86}x+8=−√
86
.
x=-\sqrt{86}-8x=−√
86
−8
5 Collect all solutions.
x=\sqrt{86}-8,-\sqrt{86}-8x=√
86
−8,−√
86
−8
x
2
+16x−22=0
2 Use the Quadratic Formula.
x=\frac{-16+2\sqrt{86}}{2},\frac{-16-2\sqrt{86}}{2}x=
2
−16+2√
86
,
2
−16−2√
86
3 Simplify solutions.
x=-8+\sqrt{86},-8-\sqrt{86}x=−8+√
86
,−8−√
86