Find the area of the polygon with vertices (1, 2) (1, -5) (5, -5) (5,2)

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

5 0

Answer:

28 square units

Step-by-step explanation:

These vertices are written in the form of their x and y coordinates. Let

A=(1,2) ; B =(1,-5) ; C =(5, -5) ; D=(5,2)

The x points are 1, 1, 5, 5

The y points are 2,-5, -5, 2

The x extremes range from 1 to 5. The length in-between is 5-1 = 4

The y extremes range from -5 to 2. The length in-between is 2-(-5) = 7

Area of the polygon enclosed by the coordinates

= 4 x 7 = 28 square units

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1. Complete the inequality below to describe the

dezoksy [38]

Domain is the entire span left to right (on the x-axis) that the graph is on. Since the graph goes from x=-4 and ends at x=4, the domain would be from -4 to 4. The circle at -4 is open, so it does not include the point at -4, just everything leading up to it. So, the domain would be

$- 4 < x \leqslant 4$

The range is similar, it is the entire span that the graph goes up and down (on the y-axis). The graph starts at the bottom at y=-2, and ends at y=5. The bottom point (4,-2) is closed, so the graph includes that point, and the top point (-4,5) is open and doesn't include the point. Therefore, the range would be

$- 2 \leqslant x < 5$