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balandron [24]
4 years ago
9

Which of the following could be values for a, b, and c so that (3x -2)(2x-7) = ax^2 + bx+c?

Mathematics
2 answers:
kirill115 [55]4 years ago
8 0

Answer:

B. A=6 B=-25, C=14

Step-by-step explanation:

(3x -2)(2x-7)

Using FOIL

= 6x^2 - 21x - 4x + 14

= 6x^2 -25x + 14

So a = 6, b = -25 and c = 14

answer

B. A=6 B=-25, C=14

horrorfan [7]4 years ago
7 0

Answer:

B

Step-by-step explanation:

Expand the factors and compare coefficients of like terms

(3x - 2)(2x - 7)

= 6x² - 21x - 4x + 14

= 6x² - 25x + 14

Compare coefficients to ax² + bx + c

ax² → 6x² ⇒ a = 6

bx → - 25x ⇒ b = - 25

14 → c ⇒ c = 14

a = 6, b= - 25, c = 14 → B

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Answer:

area = 375.8 ft^2

Step-by-step explanation:

The scale is 2 inches = 5 feet.

The room is 6.5 inches wide in the drawing. We need the real width, x.

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2x = 5 * 6.5

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The real width is 16.25 ft.

The room is 9.25 inches wide in the drawing. We need the real length, y.

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2y = 5 * 9.25

2x = 46.25

x = 23.125

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Area of rectangle = length * width

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8 0
3 years ago
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So first thousandth is the third place backwards and the first one is already right and same with the second....
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4 years ago
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6x + 4x- 1 = 2(5x + 4)
poizon [28]

Answer:

not equal

Step-by-step explanation:

first multiply 2 by 5x and by positive 4

2(5x+4)---->10x+8

10x +8 does not equal 6x +4x-1

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3 years ago
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Laura buys four BDs at $14 each and six CDs at $12 each. What is her change from $120?
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CDs

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Total

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