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fredd [130]
3 years ago
10

Jamal has a bag with 5 orange, 4 blue and 3 green marbles. He pulls out one marble without looking, puts it back in the bag and

then pulls out another marble. What is the probability that he pulled out an orange marble followed by a green one? Express your answer as a fraction in lowest terms.
Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

Step-by-step explanation:

the whole bag is made of 5 orange +4blue+3 green= 12 marbles

P of orange than green = P orange * P green = 5/12 * 3/12 = 15/144 = 5/48

you multiply when the events depend on each other to happen, so for the orange and then green to happen you need the orange and also the green

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An object is moving at the constant rate of 32 feet per second. How many yards will it travel in one minute? 10.7 yards per minu
In-s [12.5K]

1 yard = 3 feet

1 minute = 60 seconds

Multiply 32 feet per second by 60 to find feet per minute:

32 x 60 = 1920 feet per minute.

Divide total feet per minute by 3 feet to find yards per minute:

1920 / 3 =640 yards per minute.


6 0
3 years ago
The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr
aniked [119]

Answer:

(a) E(X) =  0.383

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) P(x = 4) = 0.000169

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$ E(X) =  \frac{n \times r}{N} $

$ E(X) =  \frac{10 \times 8}{209} $

$ E(X) =  \frac{80}{209} $

E(X) =  0.383

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$ P(x = 4) =  \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}} $

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$ P(x = 4) =  \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{70 \times 84944276340}{35216131179263320}

P(x = 4) = 0.000169

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0
2 years ago
Which set of angles are complementary in this diagram? Please help <3
SashulF [63]

9514 1404 393

Answer:

  (c)  ∠ECF and ∠BCF

Step-by-step explanation:

Complementary angles total 90°. Here, 90° angle BCE is divided by ray CF into two complementary angles. They necessarily have a total of 90°.

  ∠ECF and ∠BCF

6 0
2 years ago
5x=15 y 2x=6 <br> Son ecuaciones equivalentes?<br><br> PORFAVOR AYÚDENME ES EMERGENCIA
mihalych1998 [28]
Si, los dos son iguales

Cuando haces 5x=15, la división dice que x = 3. Para 2x=6 puedes usar el resultado de x=3 de la problema de antes, y cuando te usas esto va a ver que 2 de x cuando x=3 es igual a 6, y por eso 5x=15 y 2x=6 son equivalentes.
5 0
3 years ago
10 Points!! Please Help!
S_A_V [24]

Answer:

The answer is A.) R

R is in the correct correspondence with B.


4 0
3 years ago
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