Answer:
the genotype of the parent guinea pigs are as follows:
RrBb (rough, black) and Rrbb (rough, white)
Explanation:
Since the phenotype of smooth coat is present in the offspring, the parent genotype cannot have RR alleles for their coat. Similarly, the rough, black parent cannot have BB alleles in its genotype because that will not yield a white coat color in its offspring.
After making the dihybdrid cross, the probability obtained for each phenotype is given below:
rough black: 
rough white:
smooth black: 
smooth white:
Hope that answers the question, have a great day!
They both need nutrients to carry out life functions
1) To calculate the population density you first need to know how many <span>squirrels form that population.
To calculate the number of</span><span> squirrels:
1500</span> squirrels is the capacity, so it's equivalent to 100%
So how much squirrels are present in 80% of the area:
1500----100 %
x----------80 %
x= 1200 <span>squirrels
</span>
2)Population Density equals the number of squirrels divided by the land area
In the first part was calculated the number of squirrels and the exercise gives us the area in hectares so the only thing left to do is divide them.
(since this exercise doesn't specify that the area needs to be in a certain measurement we can use hectares)
Population Density = 1200/ 150
<span>The population density of the squirrels is 8 per hectare</span>
Answer:
The flooding of half part of the forest have successful separate the population of frogs in that ecosystem into two different set of frogs. This is an example of allopatric speciation, that is, the population become separated as a result of geographical barrier. This separation will make the two set of frog population to become new species. On the long run, the two species may become unable to relate sexually.
Explanation:
