What is the fraction of the percent 30 1/4

Please simplify the expression.

IRINA_888 [86]

Answer:

1) 15a - 15c + 3

2) -7n + 31 + 13m + 7p or 13m - 7n + 7p + 31

3) 44x + 6y + 3

4) 9m - 6n + 23

Step-by-step explanation:

1. Add like terms. 6a + 9a=15a. -8c - 7c=-15c

2. Add like terms. You can rearrange them in descending order based off of exponents and variables.

3. Multiply what's in parentheses first (distribute the 6). It should end up being (6y + 42x). Then you add like terms and put in descending order.

4. Distribute the (-3) to what in the parentheses. It should end up being (-6n + 15 - 3m). Then you add like terms and put the expression in descending order.

8 0

3 years ago

The house shown is a composite of more than one shape. Which of these methods would you use to find the volume of the house?

KengaRu [80]

Calculate the volume of the rectangular prism than calculate the volume of the triangular prism

4 0

3 years ago

Read 2 more answers

Susan wants to buy cherries for a party. She has $8.00 to spend. Cherries are $2.75/kg. How many kilograms of cherries can Susan

OLga [1]

Answer:you would have to divide $8.00/$2.75 and it would equal $2.90

Step-by-step explanation:This may help and if it does please thank me in the comments.

3 0

3 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$