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Alexxandr [17]
3 years ago
5

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

0,0) be defined to be .
Mathematics
1 answer:
kirill115 [55]3 years ago
8 0

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

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Given the conversion factors 12 in/1 ft and 3.28 ft/1 m, which line segment is longer?
chubhunter [2.5K]

Answer:

Line segment A

Step-by-step explanation:

The apostrophe symbol represents feet.

1 meter can be converted into 3.28'

Since 5.5' > 3.28', Line segment A is larger

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1 year ago
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Two cards are randomly selected from an ordinary playing deck.
Anna007 [38]

Answer:

The required probability is 0.048

Step-by-step explanation:

Consider the provided information.

Out of 52 card we need to select only 2.

Therefore the sample space is: ^{52}C_2=1326

One card is Ace. The number of Ace are 4 and we need to select one of them.

This can be written as: ^4C_1=4

The second card can be Ten or a Jack or a Queen or a King.

There are 4 Ten, 4 jack, 4 Queen, and 4 king in a deck and we need to select only 1 out of them.

So we can say that we need to select 1 card out of 16.

This can be written as: ^{16}C_1=16

Thus, the probability that one of the cards is an ace and the other one is either a ten, a jack, a queen or a king is:

P=\frac{16\times4}{1326}\approx0.048

Hence, the required probability is 0.048

3 0
3 years ago
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xxMikexx [17]

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Which is the equation of a parabola with a directrix at y = −3 and a focus at (5, 3)?
kramer

Answer:

y = 1/12 (x − 5)²

Step-by-step explanation:

We can solve this graphically without doing calculations.

The y component of the focus is y = 3.  Since this is above the directrix, we know this is an upward facing parabola, so it must have a positive coefficient.  That narrows the possible answers to A and C.

The x component of the focus is x = 5.  Since this is above the vertex, we know the x component of the vertex is also x = 5.

So the answer is A. y = 1/12 (x−5)².

But let's say this wasn't a multiple choice question and we needed to do calculations.  The equation of a parabola is:

y = 1/(4p) (x − h)² + k

where (h, k) is the vertex and p is the distance from the vertex to the focus.

The vertex is halfway between the focus and the directrix.  So p is half the difference of the y components:

p = (3 − (-3)) / 2

p = 3

k, the y component of the vertex, is the average:

k = (3 + (-3)) / 2

k = 0

And h, the x component of the vertex, is the same as the focus:

h = 5

So:

y = 1/(4×3) (x − 5)² + 0

y = 1/12 (x − 5)²

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For the first question

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