The sector (shaded segment + triangle) makes up 1/3 of the circle (which is evident from the fact that the labeled arc measures 120° and a full circle measures 360°). The circle has radius 96 cm, so its total area is π (96 cm)² = 9216π cm². The area of the sector is then 1/3 • 9216π cm² = 3072π cm².
The triangle is isosceles since two of its legs coincide with the radius of the circle, and the angle between these sides measures 120°, same as the arc it subtends. If b is the length of the third side in the triangle, then by the law of cosines
b² = 2 • (96 cm)² - 2 (96 cm)² cos(120°) ⇒ b = 96√3 cm
Call b the base of this triangle.
The vertex angle is 120°, so the other two angles have measure θ such that
120° + 2θ = 180°
since the interior angles of any triangle sum to 180°. Solve for θ :
2θ = 60°
θ = 30°
Draw an altitude for the triangle that connects the vertex to the base. This cuts the triangle into two smaller right triangles. Let h be the height of all these triangles. Using some trig, we find
tan(30°) = h / (b/2) ⇒ h = 48 cm
Then the area of the triangle is
1/2 bh = 1/2 • (96√3 cm) • (48 cm) = 2304√3 cm²
and the area of the shaded segment is the difference between the area of the sector and the area of the triangle:
3072π cm² - 2304√3 cm² ≈ 5660.3 cm²
Answer:
Step-by-step explanation:
What are the center and radius of the circle described by the equation x2 + y2 + 6x + 10y + 18 = 0?
Center (3.5); Radius 4
Center (-3,-5); Radius 4
O Center (3,5); Radius 16
O Center (3.5); Radius 10
x² + y²+ 6x + 10y + 18 = 0
x² + 6x + y² + 10y = -18
x² + 6x + 9 + y² + 10y + 25 = -18 + 6 + 9
x² + 3x + 3x + 9 + y² + 5y + 5y + 25 = -3
Answer:
it is rational
Step-by-step explanation:
Answer:
(-3, 3√3)
Step-by-step explanation:
Evaluate each of the coordinates. Keep or drop the "i" as your convention requires.
6(cos(120°), i·sin(120°)) = (6·cos(120°), i·6·sin(120°)) = (6(-0.5), i·6·√3/2)
= (-3, 3√3 i)
You may want the (x, y) coordinates written as (-3, 3√3).
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In the complex plane, this is -3+i·3√3.
