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ale4655 [162]
4 years ago
6

Simplify −r+7(−5r+2)

Mathematics
1 answer:
timama [110]4 years ago
8 0

Answer:

-36r +14

Step-by-step explanation:

−r+7(−5r+2)

Distribute

-r -35r +14

Combine like terms

-36r +14

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What’s the answer ??
KiRa [710]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
In the division problem 12 ÷ 2 = 6, which is the quotient?<br><br> 6<br> 2<br> 12<br> 6 and 2
Lena [83]

Answer:

6

Step-by-step explanation:

the quotient is the result to the problem, which is 6.

3 0
4 years ago
Read 2 more answers
What does it mean to multiply a number by -1?​
Ede4ka [16]
Multiplying a number by -1 makes the number a negative version of itself. For example, if you were to multiply 3 by -1, you would end up getting a product of -3.
5 0
3 years ago
A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
lana [24]

Answer:

(9)\frac{1}{12}  (10) \frac{1}{12}  (11)\frac{5}{12}  (12)\frac{1}{4}  (13)\frac{1}{6} 14)\frac{5}{36} (15)\frac{1}{12}  (16)0

Step-by-step explanation:

The sample Space of the single die rolled twice is presented below:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),}.

n(S)=36

(9)Probability of getting two numbers whose sum is 9.

The possible outcomes are:  (3, 6), (4, 5),  (5, 4)

P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}

10) Probability of getting two numbers whose sum is 4.

The possible outcomes are:  (1, 3),(2, 2),(3, 1),

P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}

11.)Find the probability of getting two numbers whose sum is less than 7.

The possible outcomes are: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4),  (3, 1), (3, 2), (3, 3),  (4, 1), (4, 2),  (5, 1)

P(\text{two numbers whose sum is less than 7})=\frac{15}{36}=\frac{5}{12}

12.Probability of getting two numbers whose sum is greater than 8

The possible outcomes are:(4, 5), (4, 6),  (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)

P(\text{two numbers whose sum is greater than 8})=\frac{9}{36}=\frac{1}{4}

(13)Probability of getting two numbers that are the same (doubles).

The possible outcomes are:(1, 1)(2, 2), (3, 3), (4, 4),  (5, 5), (6, 6)

P(\text{two numbers that are the same})=\frac{6}{36}=\frac{1}{6}

14.Probability of getting a sum of 7 given that one of the numbers is odd.

The possible outcomes are: (2, 5),  (3, 4), (4, 3), (5, 2),  (6, 1)

P(\text{getting a sum of 7 given that one of the numbers is odd.})=\frac{5}{36}

(15)Probability of getting a sum of eight given that both numbers are even numbers.

The possible outcomes are: (2, 6), (4, 4), (6, 2)

P(\text{getting a sum of eight given that both numbers are even numbers.})=\frac{3}{36}\\=\frac{1}{12}

16.Probability of getting two numbers with a sum of 14.

P(\text{getting two numbers with a sum of 14.})=\frac{0}{36}=0

4 0
4 years ago
Andrew has 212 coins, all of
Igoryamba

Answer:

158 quarters

54 dimes

Step-by-step explanation:

Let d = no. of dimes

     q = no. of quarters

10d = value of all the dimes since each dime is worth 10 cents

and 25q = value of all the quarters since each quarter is worth 25 cents

$44.90 = 4490 cents

  10d + 25q = 4490              d + q = 212

<u> - 10d - 10q = -2120</u>

             15q = 2370

                 q = 158 quarters   d + 158 = 212

                                                        d = 54 dimes

8 0
3 years ago
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