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Nesterboy [21]
4 years ago
7

Write a function shampoo_instructions() with parameter num_cycles. If num_cycles is less than 1, print "Too few.". If more than

4, print "Too many.". Else, print "N : Lather and rinse." num_cycles times, where N is the cycle number, followed by "Done.". Sample output with input: 2 1 : Lather and rinse. 2 : Lather and rinse. Done.

Computers and Technology
1 answer:
Rashid [163]4 years ago
3 0

Answer:

The code written in python and fully commented for this question is given below:

# Create the function shampoo_instructions with the num_cycles parameter input

def shampoo_instructions(num_cycles):

   # Condition if is less than 1, print too few

   if num_cycles < 1:

       print("Too few.")

   # Condition if is greater than 4, print too many

   elif num_cycles > 4:

       print("Too many.")

   # If is in inclusive range [1,4], print the Lather and rinse cycle

   else:

       # Create a for loop to print rinse cycle

       for i in range(num_cycles):

           print("{}: Lather and rinse.".format(i+1))

   # Print an end string for each execution

   print("End-------------------------------------")

# Call the function with all the conditions tested

shampoo_instructions(3)

shampoo_instructions(0)

shampoo_instructions(4)

shampoo_instructions(5)

Explanation:

I attach an image that contains the output of the execution and the source code.

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4.5 Code Practice
Alex787 [66]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

This program is written in C++.

                                                                         

#include <iostream>

using namespace std;

int main()

{

   

   string word;// variable for taking user input

   int cond;// to set condition true if user preses the stop and exit from loop

   

   cout<<"Enter word: \n";

   cin>>word;

   do// start while loop

   {

       

       

       if(word=="stop" || word =="STOP" || word == "Stop")// if user enter word stop, then program exit

       {

       cond=0;

       

       }

       else//otherwise loop continue

       {

           cout<<" You Entered "+ word +"\n";

           cout<<"Enter word: \n";

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           cond=1;

       }

   }  

   while(cond == 1);// if user don't enter word "stop" loop run continuesly.  

   cout<<"Program exit";

   

   return 0;

}

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