import random
def random_number_file_writer(nums):
f = open("random.txt", "w")
i = 0
while i < nums:
f.write(str(random.randint(1,500))+"\n")
i += 1
f.close()
def random_number_file_reader():
f = open("random.txt", "r")
total = 0
count = 0
for x in f.readlines():
total += int(x)
count += 1
print("The total of the numbers is "+str(total))
print("The number of random numbers read from the file is "+str(count))
def main():
random_number_file_writer(int(input("How many random numbers do you want to generate? ")))
random_number_file_reader()
main()
I hope this helps!
Answer:
INTRODUCTION TO JAVA
Explanation:
Java is one of the most popular programming languages out there. Released in 1995 and still widely used today, Java has many applications, including software development, mobile applications, and large systems development. Knowing Java opens a lot of possibilities for you as a developer.
Answer:
Category 5 (Cat 5) twisted pair is the least quality twisted pair wire that should be used.
Explanation:
The reason is as follows:
- Category 1 twisted pair is not suitable for transmitting data but comes in handy for telephone communications. Hence, it should not be used in a data/voice application.
- Category 2 twisted pair is suitable for data transmission, however, it can only transmit at 4Mbps which is very slow. Hence, it should not be used in a data/voice application.
- Category 3 twisted pair can transmit data with speed reaching 10Mbps which is slow for voice/data communication.
- Category 4 twisted pair can transmit data with speed reaching 16Mbps and is used in token ring networks. It is slow for communicating in a voice/data application.
- Category 5 twisted pair is the least qualified to be used in a voice/data application because it can transmit data at speeds that reach 100Mbps.
Hence, Cat 5 or Category 5 twisted pair is the least quality twisted pair that should be used in a data/voice application.
Answer:
#include<iostream>
#include <vector>
#include <list>
using namespace std;
int main(){
int a[10]={0,1,2,3, 4, 5, 6, 7, 8, 9 };
std::vector<int> v (&a[0],&a[0]+10);
std::list<int> l (&a[0],&a[0]+10);
int b[10];
for(int i=0;i<10;i++){
b[i]=a[i];
}
std::vector<int> v2(v);
std::list<int> l2(l);
for(int i=0;i<10;i++){
b[i]+=2;
}
for(int i=0;i<10;i++){
v2[i]+=3;
}
for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)
*it=*it+5;
cout<<"Each containers value are: "<<endl;
cout<<"1st array: "<<endl;
for(int i=0;i<10;i++){
cout<<a[i]<<" ";
}
cout<<"\n 1st vector: \n";
for(int i=0;i<10;i++){
cout<<v[i]<<" ";
}
cout<<"\n 1st List is:\n";
for (std::list<int>::iterator it = l.begin(); it != l.end(); it++)
cout << *it << ' ';
cout<<"\n 2nd array: "<<endl;
for(int i=0;i<10;i++){
cout<<b[i]<<" ";
}
cout<<"\n 2nd vector:\n";
for(int i=0;i<10;i++){
cout<<v2[i]<<" ";
}
cout<<"\n 2nd list:\n";
for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)
cout << *it << ' ';
return 0;
}
Explanation:
- Initialize an array, a vector and a list of type integer
.
- Create a 2nd array, vector, and list as a copy of the first array, vector, and list.
- Increase the value of each element in the array by 2
, vector by 3 and list by 5.
- Finally display the relevant results.
<span>Answer: [ 128 * (32*8 + 20 + 1) ] / [ 128 * (32*8) ] = 277/256</span>
