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stiks02 [169]
3 years ago
15

The divBySum method is intended to return the sum of all the elements in the int array parameter arr that are divisible by the i

nt parameter num. Consider the following examples, in which the array arrcontains {4, 1, 3, 6, 2, 9}.
The call divBySum(arr, 3) will return 18, which is the sum of 3, 6, and 9, since those are the only integers in arr that are divisible by 3.
The call divBySum(arr, 5) will return 0, since none of the integers in arr are divisible by 5.
Complete the divBySum method using an enhanced for loop. Assume that arr is properly declared and initialized. The method must use an enhanced for loop to earn full credit.
/** Returns the sum of all integers in arr that are divisible by num
* Precondition: num > 0
*/
public static int divBySum(int[] arr, int num)
Computers and Technology
1 answer:
iragen [17]3 years ago
8 0

Answer:

The complete method is as follows:

public static int divBySum(int[] arr, int num){        

     int sum = 0;

     for(int i:arr){

         if(i%num == 0)

         sum+=i;

     }

     return sum;

   }

Explanation:

As instructed, the program assumes that arr has been declared and initialized. So, this solution only completes the divBySum method (the main method is not included)

This line defines the method

public static int divBySum(int[] arr, int num){        

This line declares and initializes sum to 0

     int sum = 0;

This uses for each to iterate through the array elements

     for(int i:arr){

This checks if an array element is divisible by num (the second parameter)

         if(i%num == 0)

If yes, sum is updated

         sum+=i;

     }

This returns the calculated sum

     return sum;

   }

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Answer:   b. LDAP injection

Explanation:

LDAP (Lightweight Directory Access Protocol ) Injection is defined as

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So,<u> LDAP injection</u> is the attack that allows for the construction of LDAP statements based on user input statements, which can then be used to access the LDAP database or modify the database's information.

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Answer:

Answer is A. One.

Refer below.

Explanation:

A data flow cannot go directly back to the same process it leaves. There must be at least one other process that handle(s) the data flow, produce(s) some other data flow, and return(s) the original data flow to the beginning process.

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Answer:

Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.

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