J, K, and L are collinear
J is between K and L
LK = KJ + LJ
LK = 9x + 7
KJ = 2x - 3
LJ = 4x - 8
9x + 7 = (2x - 3) + (4x - 8)
9x + 7 = (2x + 4x) + (-3 - 8)
9x + 7 = 6x + -11
9x + 7 = 6x - 11
9x + 7 - 7 = 6x - 11 - 7
9x = 6x - 18
9x - 6x = 6x - 6x - 18
3x = -18
x = -6
∴ The value of x is -6
I got 0.55 when I did this problem. If I am wrong I am so sorry and please correct me.
Answer: 900π
Step-by-step explanation: To calculate the area of a circle, we do πr^2, where r is the radius. The radius is 30, so the answer is 900π.
Hope this helps!
Answer:
2 : 3
Step-by-step explanation:
<em>Hello fellow human!</em>
red : blue - 8 : 12
The ratio is divisible by 4 - (8/4) = 2 ; (12/4) = 3
Hence, 2 : 3
