Question

What is the area of a regular pentagon with an apothem of 14 inches long and a side 20 inches long?

Answer 1

Area = (5 * side length * apothem) / 2
area = (5 * 20 * 14) / 2
area = 700

(Using a calculator, I found the area to be 688.19 because the precise length of the apothem is 13.764)
http://www.1728.org/polygon.htm

Answer 2

Answer:

$\text{Area of regular pentagon is }700 inches^2$

Step-by-step explanation:

Given that a regular pentagon with an apothem of 14 inches and a side of 20 inches.

we have to find the area of pentagon.

Apothem=a=14 inches

Side of pentagon= 20 inches

$Perimeter=s=20\times 5=100 inches$

$\text{Area of regular pentagon=}\frac{1}[2}\times perimeter \times apothem$

$=\frac{1}{2}\times 100\times 14=700inches^2$

$\text{Area of regular pentagon is }700 inches^2$