Question

What is the completely factored form of 9x2 + 24x + 16?

Answer 1

It is b, (3x+4)(3x+4) = 9x2+24x+16

Answer 2

Answer: Option 2 is correct (3x+4)(3x+4)

Explanation:

we have general form of quadratic equation $ax^2+bx+c$

Given quadratic is  $9x^2+24x+16$

We will use the formula for discriminant which is $D=b^2-4ac$

On comparing the given quadratic equation with the general quadratic equation we get  a=9 , b=24,c=16

substituting the values in the formula for discriminant we will get

 $24^2-4(9)(16)$=0

Now, to find x we have formula $\frac{-b\pm\sqrt{D}} {2a}$

D=0 , b=24, c=16 substituting the values we will get

$x=\frac{-24\pm0}{2*9} =\frac{-4}{3},\frac{-4}{3}$

factors are $(x+\frac{4}{3})(x+\frac{4}{3})= (3x+4)(3x+4)$