Question

Please someone help me, it's due.

Answer 1

we are given

$f(x)=\frac{x^5}{7}$

Since, we have to find inverse function

so, we will do following steps

step-1:

we can set f(x)=y

$y=\frac{x^5}{7}$

step-2:

Switch x and y

$x=\frac{y^5}{7}$

step-3:

now, we can solve for y

$x\times 7=\frac{y^5}{7}\times 7$

$7x=y^5$

step-4:

Take radical of 5 on both sides

$\sqrt[5]{7x} =\sqrt[5]{y^5}$

we get

$y=\sqrt[5]{7x}$

$f^{-1}(x)=\sqrt[5]{7x}$............Answer

Answer 2

Hope it can help u!!!!!!!!!