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Kazeer [188]
3 years ago
12

wendy weighs 8lb less than jean if jeans weight is p lb then what is an appropriate expression fir wendys weight

Mathematics
2 answers:
PIT_PIT [208]3 years ago
4 0
The expression for Wendy's weight would be p-8.

Since Wendy is 8 pounds less than Jean, we take Jean's weight and subtract 8.  If Jean's weight is p, then Wendy's would be p-8.
Marizza181 [45]3 years ago
4 0

Answer:

p-8

Step-by-step explanation:

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Find the common ratio of the geometric sequence 4, -20, 100, -500, ...
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Answer:

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6 0
2 years ago
Write the next three terms of the arithmetic sequence.
JulijaS [17]

The next three terms are: 1/6 , 0 and -1/6

Step-by-step explanation:

Given sequence is:

\frac{5}{6} , \frac{2}{3} ,\frac{1}{2}, \frac{1}{3} ...

First of all, we have to find the common difference

here\\a_1 = \frac{5}{6}\\a_2 = \frac{2}{3}\\a_3 = \frac{1}{2}\\a_4 = \frac{1}{3}\\d = a_2-a_1 = \frac{2}{3} -\frac{5}{6} = \frac{4-5}{6} = -\frac{1}{6}\\d = a_3 - a_2 = \frac{1}{2} - \frac{2}{3} = \frac{3-4}{6} = =\frac{1}{6}

The common difference is -1/6

We can simply add -1/6 to the previous term to find the next terms so,

Adding -1/6 to 1/3

\frac{1}{3} - \frac{1}{6} = \frac{2-1}{6} = \frac{1}{6}\\\frac{1}{6} - \frac{1}{6} = 0\\0-\frac{1}{6} = -\frac{1}{6}

Hence,

The next three terms are: 1/6 , 0 and -1/6

Keywords: Arithmetic sequence, common difference

Learn more about arithmetic sequence at:

  • brainly.com/question/2495851
  • brainly.com/question/2491745

#LearnwithBrainly

4 0
3 years ago
NEED HELP ASAP WILL GIVE HIGH REWARD
VikaD [51]
The answer for this is is 35 370 93 and i got that now by using guzmos
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9 months ago
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The surface area of two similar solids are 340yd^2 and 1,158yd^2. The volume of the larger solid is 1,712yd^2. What is the volum
solong [7]
The ratio of the areas is 340/1158 = 170/579thus the ratio of the side lengths is sqrt(170)/sqrt(579)  = .5418the ratio of volumes is the side length ratio cubed = .5418^3 = .159Volume of smaller solid  = (.159)(1712) = 272.37
7 0
3 years ago
How do you do this and what’s the answer to this I been stuck on this question for litterly 20 mins
Vsevolod [243]

\bf T=2\pi \sqrt{\cfrac{L}{g}}\implies \stackrel{\textit{squaring both sides}}{(T)^2=\left( 2\pi \sqrt{\cfrac{L}{g}}\ \right)^2}\implies T^2=2^2\pi^2\sqrt{\left( \cfrac{L}{g} \right)^2} \\\\\\ T^2=4\pi^2\cfrac{L}{g}\implies T^2=\cfrac{4\pi^2L}{g}\implies gT^2=4\pi^2L\implies g=\cfrac{4\pi^2L}{T^2}

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