Answer is C! Hope it helps
The solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change, slope or gradient
<h3>How to determine the solution to the system?</h3>
A system of linear equations is a collection of at least two linear equations.
In this case, the system of equations is given as
2x- y = 3
y - x = 1
Make y the subject in the second equation, by adding x to both sides of the equation
y - x + x = x + 1
This gives
y = x + 1
Substitute y = x + 1 in 2x- y = 3
2x- x - 1 = 3
Evaluate the like terms
x = 4
Substitute x = 4 in y = x + 1
y = 4 + 1
Evaluate
y = 5
Hence, the solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
Read more about system of linear equations at
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Answer:
Step-by-step explanation:
We are given that
Length of rope=l=160 feet
Radius of quadrant of circle=r=160 feet
We have to find the maximum grazing area of the cow.
We know that
Area of quadrant of circle=
Where 
Using the formula
Area grazed by cow=
Area grazed by cow=
Answer:
The original selling price would be $ 515.87 ( approx )
Step-by-step explanation:
Let x be the original selling price ( in dollars ),
After marking down 10%,
New selling price = x - 10% of x = x - 0.1x = 0.9x
Again after marking down 30%,
Final selling price = 0.9x - 30% of 0.9x
= 0.9x - 0.3 × 0.9x
= 0.9x - 0.27x
= 0.63x
According to the question,
0.63x = 325
Hence, the original selling price would be $ 515.87.
Answer:
49+0.89c
Step-by-step explanation:
This should be the answer good luck :)
