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Natasha2012 [34]
3 years ago
11

Write the inverse function for the function, ƒ(x) = 1/2x + 4. Then, find the value of ƒ -1(4). Type the answer exactly in this f

orm.
ƒ -1(x) = ____a0 x ________a1 _______a2
ƒ -1(4) = ______a3
Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0
We can get the inverse function by first setting f(x) = y, solving for x, and after that switching y and x. So, let's solve for x:
f(x)= \frac{1}{2}x+4
y= \frac{1}{2}x+4
2(y-4)=x
2x-4=y=f (x)^{-1}

Then, just plug in 4 for x, and solve:
2(4)-4= f (x)^{-1}
4=f (x)^{-1}

There you have your answer.

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point a is on line segment RT. Given ST = 2x, RT = 4x, and RS = 4x -4 determine the numerical length of RS
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Forty nine x plus 15x -ggsg and y will get 13
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3 years ago
A grid model with 100 squares. 73 squares are shaded. What percent of the model is shaded? What is the equivalent ratio? What is
viva [34]

Answer:

73%

Step-by-step explanation:

First, you'll divide the total squares by 100 to get how much is one percent. Then, you divide the shaded squares by the value of 1%. And you'll get how many percents are shaded.

For equivalent decimal, you divide the number by 100.

Then for equivalent decimal, you get the percent and 100.

p =100/100=1\\73/1=73\\=0.73\\=\frac{73}{100}

5 0
3 years ago
How many terms in 9a+11p
Naddik [55]

Answer:

2 terms

Step-by-step explanation:

Terms are nothing but the mixtures of co-effecients and their variables..

Here, 9a is one term while 11p is the other

7 0
3 years ago
Read 2 more answers
What is the least common multipul of 6 and 8?
Bogdan [553]

Answer:

Step-by-step explanation:

24

The LCM of 6 and 8 is 24. To find the least common multiple (LCM) of 6 and 8, we need to find the multiples of 6 and 8 (multiples of 6 = 6, 12, 18, 24; multiples of 8 = 8, 16, 24, 32) and choose the smallest multiple that is exactly divisible by 6 and 8, i.e., 24.

5 0
3 years ago
Is RS perpendicular to DF? Select Yes or No for each statement. R (6, −2), S (−1, 8), D (−1, 11), and F (11 ,4) R (1, 3), S (4,7
guajiro [1.7K]

I'll do the first one to get you started.  

Find the slope of the line between R (6,-2) and S (-1,8) to get

m = (y2-y1)/(x2-x1)

m = (8-(-2))/(-1-6)

m = (8+2)/(-1-6)

m = 10/(-7)

m = -10/7

The slope of line RS is -10/7

Next, we find the slope of line DF

m = (y2 - y1)/(x2 - x1)

m = (4-11)/(11-(-1))

m = (4-11)/(11+1)

m = -7/12

From here, we multiply the two slope values

(slope of RS)*(slope of DF) = (-10/7)*(-7/12)

(slope of RS)*(slope of DF) = (-10*(-7))/(7*12)

(slope of RS)*(slope of DF) = 10/12

(slope of RS)*(slope of DF) = 5/6

Because the result is not -1, this means we do not have perpendicular lines here. Any pair of perpendicular lines always has their slopes multiply to -1. This is assuming neither line is vertical.

I'll let you do the two other ones. Let me know what you get so I can check your work.

3 0
3 years ago
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