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Natasha2012 [34]
3 years ago
11

Write the inverse function for the function, ƒ(x) = 1/2x + 4. Then, find the value of ƒ -1(4). Type the answer exactly in this f

orm.
ƒ -1(x) = ____a0 x ________a1 _______a2
ƒ -1(4) = ______a3
Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0
We can get the inverse function by first setting f(x) = y, solving for x, and after that switching y and x. So, let's solve for x:
f(x)= \frac{1}{2}x+4
y= \frac{1}{2}x+4
2(y-4)=x
2x-4=y=f (x)^{-1}

Then, just plug in 4 for x, and solve:
2(4)-4= f (x)^{-1}
4=f (x)^{-1}

There you have your answer.

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Answer:

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Step-by-step explanation:

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3 years ago
(ab^2 x -b^4a^3)^2<br><br> What is the answers
Umnica [9.8K]

Answer:

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

Step-by-step explanation:

Given the expression

\left(ab^2\:x\:-b^4a^3\right)^2

solving the expression

\left(ab^2\:x\:-b^4a^3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2

a=ab^2x,\:\:b=b^4a^3

so the expression becomes

=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2

=a^2b^4x^2-2a^4b^6x+a^6b^8

Thus,

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

3 0
3 years ago
Mrs. Shultz went to New York to do her Christmas shopping. She took a cab to go into the city and they charged her a flat fee of
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12 miles

Step-by-step explanation:

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Help number 2 ASAP thank you
emmasim [6.3K]

Answer:

yes

Step-by-step explanation:

sorry if it's wrong

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Answer:

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Step-by-step explanation:

Check the photo below for the details.

:)

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4 years ago
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