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avanturin [10]
3 years ago
15

Wireless networks are the most difficult type of network to set up true or false

Computers and Technology
1 answer:
Elden [556K]3 years ago
5 0

Answer:

The answer is "False".

Explanation:

  • Wireless networks are a network, set up to communicate between computers and other network devices using a radio signals frequency. It is also sometimes referred to as a WiFi or WLAN network. Due to the easy set-up and cabling feature, this network is now popular.  
  • A Wireless network uses a signal that is transmitted and decoded by a wireless router. The information is then sent to the internet via a wired Ethernet connection.

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____ are designed to be used with everyday objects, such as home appliances, gaming consoles, digital cameras, e-readers, digita
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Embedded Operating Systems are designed to be used with everyday objects, such as home appliances, gaming consoles, digital cameras, e-readers, digital photo frames, ATMs, toys, watches, GPS systems, home medical devices, voting terminals, and cars.

6 0
3 years ago
Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi
Kay [80]

Answer:

The algorithm is very similar to the algorithm of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.

Algorithm:

Let A = (a1, a2, . . . , an).

Function CountSigInv(A[1...n])

if n = 1 return 0; //base case

Let L := A[1...floor(n/2)]; // Get the first half of A

Let R := A[floor(n/2)+1...n]; // Get the second half of A

//Recurse on L. Return B, the sorted L,

//and x, the number of significant inversions in $L$

Let B, x := CountSigInv(L);

Let C, y := CountSigInv(R); //Do the counting of significant split inversions

Let i := 1;

Let j := 1;

Let z := 0;

// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;

//the normal merge-sort process i := 1; j := 1;

//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);

Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).

Explanation:

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3 years ago
_____ allows you to use the internet for making phone calls instead of leasing traditional telephone lines from the phone compan
TEA [102]
Using a browser would help in doing that.
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3 years ago
(iii) ............ characters can be stored in memo field. (a) 50 (b) 64000 (c) 255 (d) 200 ​
Svetlanka [38]

Answer:

(b) 64000

Explanation:

Assuming that the "Memo" being mentioned is a Microsoft Access memo field, it can hold up to 64,000 characters, even in the more recent version of the application where the "Memo" is now know as the "Long Text" field.

According to microsoft.com, "In earlier versions of Access, we used the Memo data type to store large amounts of text... the Long Text field works the same as the Memo field of old... [it] can only display the first 64,000 characters."

<em>Please put "Brainliest" on my answer if it helped you out the most!</em>

<em>(Further Reading) If you're still confused, I suggest you search up the following:</em>

<em>- Microsoft Access Long Text character limit</em>

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2 years ago
It is easier to make an object move across the screen by using the tweening function rather than creating each individual frame
Vesna [10]
Uhhhh I believe it’s true if it’s wrong I’m srry ....
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3 years ago
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