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Elden [556K]
3 years ago
10

An elevator can hold a maximum of 1,500 pounds. Eight people need to use the elevator. Bill had some

Mathematics
1 answer:
Anna11 [10]3 years ago
6 0
Well first we need to determine what each choices ( mean, median, mode, interquartile range) means.
Mean- average of a set of numbers
Median - middle number of a set of numbers
Mode- number that appears the most in a set of numbers
Interquartile range- find median of set of numbers and separate the set into 3 equal sections total. Subtract the 3rd section from the 1st section. So you can find the range or span of numbers.

If you want to build an elevator that can hold a maximum of 1,500 pounds, i think the most important fact you need to know about weight is the average weight that all the people weighs so you can know what to expect<span />
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ERROR ANALYSIS Describe and correct the error in solving the equation.
Crank

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6 0
3 years ago
A Normal distribution has mean µ = 61.6. Find it’s standard deviation if 20% of the values are greater than 70. (Hint--use the z
statuscvo [17]

Answer:

The value is  \sigma  = 9.976

Step-by-step explanation:

From the question we are told that

   The mean is \mu = 61.6

Given that 20% of the values are greater than 70, the z-score to  the right of the curve  corresponding to 20% (0.2) of the values is

     z-score = 0.842  

Generally this z-score is mathematically represented as

       z-score  = \frac{x - \mu }{\sigma }

Here  x = 70  

So

     0.842 = \frac{70 - 61.6  }{\sigma }

=>   \sigma  = 9.976

4 0
3 years ago
#3 please im so bad with area lol
ANTONII [103]
Base times height is the formula for area I’m pretty sure
4 0
3 years ago
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A football team gained 9 yards on one play and then lost 22 yards on the next. Write a sum of integers to find the overall chang
Phoenix [80]

Answer:

+9-22=-13

Step-by-step explanation:

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4 0
4 years ago
Help please<br> 3^4 + 4 ⋅ 5 = ____. (Input whole numbers only.) (20 points)
Akimi4 [234]

Answer:

101

Step-by-step explanation:

3^4 = 81

4 x 5  20

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3 0
3 years ago
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