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mars1129 [50]
3 years ago
14

What should happen if a good experiment is replicated?

Mathematics
2 answers:
Ahat [919]3 years ago
6 0

Answer:

The results will be similar

Step-by-step explanation:

This should be the case because it is being replicated not completely the same but not completely different.

trasher [3.6K]3 years ago
5 0

Answer:

D

Step-by-step explanation:

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Physics students drop a ball from the top of a 100 foot high building and model its height as a function time with the equation
pishuonlain [190]

When the ball hits the ground, the height is 0.

0 = 100 - 16t²

0 = (10 - 4t)(10 + 4t)

0 = 10 - 4t     or     0 = 10 + 4t

4t = 10          or       -4t = 10

 t = \frac{10}{4}             or          t = -\frac{10}{4}

Time cannot be negative (unless you have a time machine) so disregard  -\frac{10}{4}

Answer: t = \frac{5}{2} = 2.5 seconds

6 0
3 years ago
4000-1375 and I need work
zheka24 [161]



4000
-1375
———

Take 1 from the number 4 and have it go down the line of zeros.

39910
-1375
———-

Subtract

39910
-1375
———-
2,625

I hope this helped!
8 0
3 years ago
Please help!!
Rama09 [41]
The associative property of addition is pretty much just any numbers in place of these: a + (b + c) = (a + b) + c. Therefore, your answer would be d) (6 + 1) + 9 = 6 + (1 + 9)
6 0
3 years ago
Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. ​(a) Descr
Daniel [21]

Answer:

(a) The sampling distribution of\overline{X} = Population mean = 79

(b)  P ( \overline{X} greater than 81.2 ) =  0.1357

(c) P (\overline{X} less than or equals 74.4 ) = .0107

(d) P (77.6 less than \overline{X} less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean (\nu) = 79

Standard deviation (\sigma ) = 18

​(a) Describe the sampling distribution of \overline{X}

For large sample using central limit theorem

the sampling distribution of\overline{X} = Population mean = 79

​(b) What is Upper P ( \overline{X} greater than 81.2 )​ =

P(\overline{X}> 81.2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})

                    =  P(Z> 1.1)

                    = 1 - P(Z<   1.1)

                    = 1 - .8643 =

                    = 0.1357

(c) What is Upper P (\overline{X} less than or equals 74.4 ) =

P(\overline{X}\leq  74.4) = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{74.4- 79}{\frac{18}{\sqrt{81}}})

                    = P(Z\leq  -2.3)

                    = .0107

​(d) What is Upper P (77.6 less than \overline{X} less than 83.2 ) =

P(77.6< \overline{X}<   83.2) = P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{83.2- 79}{\frac{18}{\sqrt{81}}})

                                = P(- 0.7< Z<   2.1)

                                 = (Z<   2.1) - (Z<   -0.7)

                                  = 0.9821 - .2420

                                   = 0.7401

3 0
3 years ago
19/20 into a percentage
Westkost [7]

Answer:

it will be 95%

hope that helps

3 0
3 years ago
Read 2 more answers
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