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Mademuasel [1]
3 years ago
5

A builder set up a wooden frame in which to pour concrete for a foundation to a house. The length of the wooden frame is 24 feet

. The width is 32 feet. The diagonal is 40 feet. Which best describes the foundation?
The foundation cannot be a rectangle: 24+32≠40

The foundation cannot be a rectangle: (24+32)^2≠40^2

The foundation cannot be a rectangle: √24^2+32^2≠40^2

The foundation may be a rectangle: 24^2+32^2=40

^2
Mathematics
2 answers:
ruslelena [56]3 years ago
5 0

I have drawn a figure for the foundation of a frame with dimension 24 x 32 and diagonal.

For triangle ABD, if it's satisfy the Pythagorean theorem then ABCD will be a recatngle.

Pythagorean formula is:

a² + b² = c²

Where c is the hypotenuse and a, b are the legs of the triangle.

From triangle ABD:

AB² +BD² = AD²

24² + 32² = 40²

576 + 1024 = 1600 Simplify each sides separately.

1600 = 1600

From above result , 1600 = 1600 is true.

So, ABD is a right triangle, similarly ACD will also be right triangle.

Hence, ∠B and ∠C are right triangles.

So, ABCD is a rectangle.

Hence, the last choice is correct.

Hope this helps you!.

miss Akunina [59]3 years ago
3 0

Answer:

D. The foundation may be a rectangle: 24^2 + 32^2 = 40^2

Step-by-step explanation:

I just took the quiz on edge

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Susie has a bag of marbles containing 3 Red, 7 Green, and 10 Blue marbles.
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Answer:

1) a) 0.0945

b) 0.1062

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5) 0.0056

Step-by-step explanation:

Since there are 3 Red, 7 Green, and 10 Blue marbles.

Total number of marbles N = 20

Probability (Red) = 3/20

Probability (Green) = 7/20

Probability (Blue) = 10/20

1) the probability of picking 5 marbles and getting at least one red marble

A) with replacement

P(at least 1 red of 5)= (3/20 * 17/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 3/20 * 17/20 * 17/20)

P(at least 1 red of 5) = 0.0783 +0.0138 + 0.0024 = 0.0945

B) without replacement

P(at least 1 red of 5) = ( 3/20 * 17/19* 16/18 * 15/17 * 14/16) + (3/20 * 2/19 * 17/18 * 16/17 * 15/16) + (3/20 * 2/19 * 1/18 * 17/17 * 16/16)

P(at least 1 red of 5) = 0.0921 + 0.01316 + 0.0009 = 0.1062

2) the probability of picking 6 marbles having 2 of each color

A) with replacement

P( 6, 2 of each) = 3/20 * 3/20 * 7/20 * 7/20 * 10/20 * 10/20

P( 6, 2 of each) = 0.0138

B) without replacement

P( 6, 2 of each) = 3/20 * 2/19 * 7/18 * 6/17 * 10/16 * 9/15

P( 6, 2 of each) = 0.00081

3) Pick 8 marbles: 4 green and 4 blue

A) with replacement

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P(8, 4G and 4 B) = 0.00094

B) without replacement

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Only Green and Blue marbles are more than 6

P(at least 6 marbles of the same color) = (7/20*6/19*5/18*4/17*3/16*2/15) + (10/20*9/19*8/18*7/17*6/16*5/15)

= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

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C = 300 cents

Therefore, You will have to pay

(1 + 0.0056) 300 cent = 301.68 cents to be sure of getting at least 6 marbles of the same color

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= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

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Answer:

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