Equations:
2x+105=-3x+130
<em>subtract</em><em> </em><em>2x</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em>
<em>105</em><em>=</em><em> </em><em>-5x</em><em>+</em><em>130</em>
<em>Subtract</em><em> </em><em>130</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em>
<em>-5x</em><em>=</em><em> </em><em>-25</em>
<em>isolate</em><em> </em><em>the</em><em> </em><em>variable</em>
<em>x</em><em>=</em><em>5</em><em> </em>
<u>Plug</u><u> </u><u>back</u><u> </u><u>in</u>
<u>2</u><u>(</u><u>5</u><u>)</u><u>+</u><u>105</u><u>=</u><u> </u><u>-3</u><u>(</u><u>5</u><u>)</u><u>+</u><u>130</u>
<u>115</u><u>=</u><u> </u><u> </u><u>115</u>
Answer:

Step-by-step explanation:










l4ynhrnhebegbyev3tv3tv3tv3g 3f eg ef ev3tv3tv
Answer:
Explained below.
Step-by-step explanation:
The random variable <em>X</em> is defined as the number of stars in a given volume of space.

The probability mass function of <em>X</em> is:

(7)
Compute the probability of exactly two stars in 16 cubic light-years as follows:

(8)
Compute the probability of three or more stars in 16 cubic light-years as follows:

(9)
In 16 cubic light years there is only 1 star.
Then in 1 cubic light years there will be, (1/16) stars.
Then in 4 cubic light years there will be, 4 × (1/16) = (1/4) stars.
(10)
In 16 cubic light years there is only 1 star.
Then in 1 cubic light years there will be, (1/16) stars.
Then in <em>t</em> cubic light years there will be, [<em>t</em> × (1/16)] stars.
Answer:
The answer would be 9,
Step-by-step explanation:
because it is closer to 9 than 8.