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Diano4ka-milaya [45]
3 years ago
9

Sketch the quadratic function f(x) = x2 + 4x + 3. Which key feature of the graph is given incorrectly?

Mathematics
2 answers:
tangare [24]3 years ago
8 0

Given quadratic function f(x)= x^2+4x+3.

Let us find vertex of the graph first.

x-coordinate of the vertex = -b/2a = -4/2(1) = -4/2 = -2.

y-coordinate of the vertex = (-2)^2+4(-2)+3 = 4-8+3 = -1.

Therefore, vertex is at (-2,-1).

The leading coefficient of quadratic function f(x)= x^2+4x+3 is 1.

And it's a positive number.

So, the parabola open up and it would have a minimum at it's vertex point.

Let us find some more points on the graph :

x=-3

(-3)^2 +4(-3) +3 = 9 -12 +3 =0

x=-1

(-1)^2 +4(-1) +3 = 1 -4 +3 = 0.

<em>From the graph, we can see vertex is at (-2,-1) and x-intercepts at (-1,0), (-3,0) and y-intercept at (0,3).</em>

Therefore, following is the key feature of the graph is given incorrectly:

<h2>B) y-intercept (0, 2) </h2>

horsena [70]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Answer:

3.6661

3.6661

A, Adding a constant does nothing to the standard deviation

Step-by-step explanation:

I'm gonna assume s=standard deviation

The standard deviation is just the square root of the second moment minus the first moment squared

Because we were not told otherwise I think it's pretty safe to assume that all events are equally likely

Let's start by calculating the first moment (AKA The mean)

1/5(8+16+14+8+16)= 12.4

Let's then find the second moment

1/5(8²+16²+14²+8²+16²)= 167.2

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b.

While I could just tell you that adding something to the standard deviation (and the variane as well) doesn't do anything let's calculate it for fun

same process

.2(16+24+22+16+24)= 20.4

.2(16²+24²+22²+16²+24²)=429.6

√(429.6-20.4²)= 3.6661

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3 years ago
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The area of the trapezoid is the product of the height and half the sum of the base lengths, hence is the square of half the sum of the base lengths.

... Area = ((16 cm +30 cm)/2)² = (23 cm)² = 529 cm²

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