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yawa3891 [41]
4 years ago
8

What is the first step in solving x^2+2x+3=0

Mathematics
2 answers:
Westkost [7]4 years ago
7 0
First subtract three from both sides. then you have x^{2} +2x=-3 and you solve from there
Neporo4naja [7]4 years ago
6 0
Is the question asking by completing the square? 
X^2+2X+3=0
X^2+2x+1+2=0
(x+1)^2+2=0
(x+1)^2=-2
x+1=squr root 2i or x+1=-sqr root 2i
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<em>The perimeter of the rhombus is 20 cm</em>

Step-by-step explanation:

<u>Perimeter of a Rhombus</u>

Given the lengths of the two diagonals of a rhombus, let's call them a and b,  the perimeter of the rhombus is given by:

P=2\sqrt{a^2+b^2}

The values of the diagonals provided by the question are a=6 cm, b=8 cm, thus the perimeter is:

P=2\sqrt{6^2+8^2}

P=2\sqrt{36+64}

P=2\sqrt{100}=2*10

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