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yawa3891 [41]
3 years ago
8

What is the first step in solving x^2+2x+3=0

Mathematics
2 answers:
Westkost [7]3 years ago
7 0
First subtract three from both sides. then you have x^{2} +2x=-3 and you solve from there
Neporo4naja [7]3 years ago
6 0
Is the question asking by completing the square? 
X^2+2X+3=0
X^2+2x+1+2=0
(x+1)^2+2=0
(x+1)^2=-2
x+1=squr root 2i or x+1=-sqr root 2i
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How can we eliminate an imaginary from the denominator? Simplify 2/(3+5i) to demonstrate.
alexira [117]
Multiply by the conjugate and simplify
3/17 - 5i/17

Hope this helps! :)
7 0
3 years ago
Is -30 - (-52) positive or negative?
Luba_88 [7]

Answer:

positive

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
4-2x=11 how do I solve
Bingel [31]

Hey there!☺

Answer:\boxed{x=\frac{-7}{2}}

Explanation:

4-2x=11

In our first step, we will simplify both sides of the equation:

4+-2x=11\\-2x+4=11

Now subtract 4 from both sides:

-2x+4-4=11-4\\-2x=7

In our last step, we will divide both sides by -2:

\frac{-2x}{2}=\frac{7}{-2}\\  x=\frac{-7}{2}

x=-7/2 is your answer.

Hope this helps!☺

3 0
3 years ago
Solve for x: −1 < x + 3 < 5
Gnesinka [82]

Answer:

-4<x<2

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask ÷)

7 0
3 years ago
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
Jobisdone [24]

Answer:

f(x)=x^4-9x^2-50x-150

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))

We expand to get:f(x)=(x^2-2x-15)(x^2+2x+10)

We expand further to get:\

f(x)=x^4-9x^2-50x-150

3 0
3 years ago
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