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satela [25.4K]
4 years ago
15

6. Jessie sorted the coins in her bank. Shemade 7 stacks of 6 dimes and 8 stacksof 5 nickels. She then found 1 dime and1 nickel.

How many dimes and nickelsdoes Jessie have in all? (Lesson 2.12)

Mathematics
2 answers:
Salsk061 [2.6K]4 years ago
6 0
7 stacks of 6 dimes = 6•7 which is 42
8 stacks of 5 nickles = 8•5 which is 40
1 dime + 1 nickle
Add all of them together .......42+40+1+1=84

Hope this helped!❤️
Leokris [45]4 years ago
3 0
Lets write down the information that we know.

Jessie has 7 stacks of 6 dimes, so Jessie has a total of 6*7 dimes

Dimes=7*6=42dimes  

Jessie has 42 dimes, but then she found another one so lets add one more dime.

42+1=43 dimes

Jessie has 8 stacks of 5 nickels, so Jessie has 8*5 nickels

Nickels=8*5=40nickels

Jessie has 40 nickels, but then she found another one so lets add 1 to the total number of nickels.

40+1=41nickels

Now we can answer the question.

How many dimes and nickels does jessie have in all?

nickels+dimes=
41+43=84 coins

Jessie has 84 coins in total
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a rectangle field has an anrea of 40cm^2. if one side of the field is 3m longer than the other side, find the new area of the fi
oksian1 [2.3K]

The area of the field where the length of each side is increased by 10% is 48.4 cm^{2}.

Step-by-step explanation:

The given is,

               A rectangle field has an area of 40 cm^{2}

               If one side of the field is 3 cm longer than the other side

               The length of new area in each side is increased by 10%

Step:1

          Let,

                          b - One side of rectangle

                          l - Other side of rectangle

          From given.

                         l -  b +3

           Formula for area of rectangle,

                   Area, a = lb      

                          40 = ( b+3) × b

                         40 = b^{2} + 3b

           Solving the above the equation,

                          b = 5 cm

                            l = 8 cm

Step:2

          If the area of rectangle increased by 10%,

                            l = 8 + ( 8 × \frac{10}{100} )

                              = 8.8

                           b = 5 + ( 5 × \frac{10}{100} )

                              = 5.5

         Area of rectangle is,

                      a = ( 8.8 × 5.5 )

                        = 48.4 square centimeters

Result:

        The area of the field where the length of each side is increased by 10% is 48.4 cm^{2}, if a rectangle field has an area of 40 square centimeters and one side of the field is 3 cm longer than the other side.

             

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