All categories

3 years ago

Which statement about London dispersion forces is true?

Chemistry

2 answers:

Lady bird [3.3K]3 years ago

7 0

I am positive it is a

Vera_Pavlovna [14]3 years ago

6 0

The answer to the question is A.

You might be interested in

3- Given 90.0 g C6H1206 a- How many moles of Glucose are present in 90.0 g of glucose?

Nesterboy [21]

molar mass = 180.18

$90.0 \: g \times \frac{1 \: mol}{180.18 \: g} = 0.4995004995 \: mol$

$= 0.500 \: mol$

8 0

3 years ago

Both of janies parents have dark hair. how likely is janie to have blonde hair?

sveticcg [70]

Answer:

The probability of Janie to have blonde hair would be a slim 13% to a 34%.

Explanation:

Not 100% sure but best estimation I can come up with.

3 0

3 years ago

A concentration cell consists of two Zn/Zn2+ half-cells. The concentration of Zn2+ in one of the half-cells is 2.0 M and the con

inna [77]

Answer: The EMF of the cell is coming when the cell having diluted concentration is getting oxidized.

Explanation:

We are given a cell which contains two $Zn/Zn^{2+}$ half cells. This means that the standard electrode potential of the cell will be 0.

For a reaction to be spontaneous, the EMF of the cell must be positive. If the EMF of the cell is negative, the reaction will be non-spontaneous and will not take place.

For a reaction to be spontaneous, the diluted cell must get oxidized.

The half reaction for the given cell follows:

Oxidation half reaction: $Zn\rightarrow Zn^{2+}(1.0\times 10^{-3}M)+2e^-$

Reduction half reaction: $Zn^{2+}(2.0M)+2e^-\rightarrow Zn$

Net reaction: $Zn^{2+}(2.0M)\rightarrow Zn^{2+}(1.0\times 10^{-3}M)$

To calculate the EMF of the cell, we use Nernst equation:

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}_\text{{(diluted)}}]}{[Zn^{2+}_{\text{(concentrated)}}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = ?

$[Zn^{2+}_{\text{(diluted)}}]$ = $1.0\times 10^{-3}M$

$[Zn^{2+}_{\text{(concentrated)}}]$ = 2.0 M

Putting values in above equation, we get:

$E_{cell}=0-\frac{0.0592}{2}\log \frac{1.0\times 10^{-3}M}{2.0M}$

$E_{cell}=0.097V$

Hence, the EMF of the cell is coming when the cell having diluted concentration is getting oxidized.

6 0

3 years ago

Which of the following best demonstrates kinetic energy?

Novay_Z [31]

Hey there!

Kinetic energy means that something is in motion.

Therefore, the answer would be B. Bird in flight because it’s the only choice that suggests is moving.

Hope this helps!

God bless ❤️

xXxGolferGirlxXx

3 0

3 years ago

Read 2 more answers

Express the product of 5.4 mm and 6.02 mm using the correct number of significant digits.

krek1111 [17]

we are asked to multiply 5.4 mm by 6.02 mm

5.4 mm has 2 significant figures

6.02 mm has 3 significant figures

When multiplying these 2 numbers the answer should have the least number of significant figures

From the 2 numbers the least number of significant figures is 2 , therefore answer should be rounded off to 2 significant numbers

5.4 x 6.02 = 32.5 rounded off is 33

Answer is b. 33 m^2

5 0

3 years ago