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Answer:
The correct answer is B) electronegativities of the bonded atoms in a molecule of the compound .
Explanation:
When two atoms forming a bond differ in their electronegativities at that time bond polarity is generated
In simple words a bond will be polar when the bonding electrons are not equally shared by two atoms.As a result the atom attract the bonding electron pair towards itself gain partial negative charge and the other atom gains partial positive charge.
For HCl is a polar compound because H and Cl atom differ in their electronegativities,as a result the bonding electron pair is not shared equally by H and Cl atoms.
Answer:
it depends where you live really... lol
The copper atom is oxidized while the silver is reduced.
<h3>What is a redox reaction?</h3>
A redox reaction is one that occurs between an oxidizing agent and a reducing agent. One specie is oxidized while the other specie is reduced in the reaction.
In this case, the oxidizing agent is the silver and the reducing agent is the copper atom. The copper atom is oxidized while the silver is reduced.
The complete equation is;
Cu(s) + 2AgNO3(aq) -----> Cu(NO3)2(aq) + Ag(s)
Ionically;
Cu(s) + 2Ag^+ -----> Cu^2+(aq) + Ag(s)
Learn more about redox reaction:brainly.com/question/13293425
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Answer:
Please see the complete formt of the question below
Chlorine gas can be made from the reaction of manganese dioxide with hydrochloric acid.
MnO₂(s) + HCl(aq) → MnCl₂(aq) + H₂O(l) + Cl₂(g)
According to the above reaction, determine the limiting reactant when 5.6 moles of MnO₂ are reacted with 7.5 moles of HCl.
The answer to the above question is
The limiting reactant is the MnO₂
Explanation:
To solve this, we note that one mole of MnO₂ reacts with one mole of HCl to produce one mole of MnCl₂, one mole of H₂O and one mole of Cl₂
Molar mass of MnO₂ = 86.9368 g/mol
Molar mass of HCl = 36.46 g/mol
From the stoichiometry of the reaction, 5.6 moles of MnO₂ will react with 5.6 moles of HCl to produce 5.6 moles of H₂O and 5.6 moles of Cl₂
However there are 7.5 moles of HCL therefore there will be an extra 7.5-5.6 or 1.9 moles of HCl remaining when the reaction is completed