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gayaneshka [121]

3 years ago

8

Competition is likely to occur between which two organisms?

1 answer:

MatroZZZ [7]3 years ago

7 0

<h3>Full question found from another source:</h3>

5. Competition is likely to occur between which two organisms?

A Owls and bacteria

B Deer and butterflies

C Grass and strawberry plants

D Goldfish and rabbits

Answer:

C

Explanation:

Grass and strawberry plants compete for the same resources such as nutrients, water, habitat, and sunlight.

Bacteria and owls rely on completely different resources and mechanisms to survive - bacteria are single cell organisms and owl are complex birds

Deer and butterflies are also are not in competition with eachother - they don't occupy the same habitats, eat the same food or have the same prey.

Goldfish and rabbits will never encounter eachother, given that one lives in water and one lives on land. They do not compete for the same food source or habitat.

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2. Write the chemical equations for the neutralization reactions that occurred when HCL and NaOH were added to the buffer soluti

lutik1710 [3]

Answer:

HCI(aq)+CH3COONa(s) ----> CH3COOH(aq)+NaCl(s)

NaOH(aq)+CH3COOH(aq) ----> CH3COONa(s)+H2O(l)

Explanation:

A buffer is a solution that resists changes in acidity or alkalinity. A buffer is able to neutralize a little amount of acid or base thereby maintaining the pH of the system at a steady value.

A buffer may be an aqueous solution of a weak acid and its conjugate base or a weak base and its conjugate acid.

The equations for the neutralizations that occurred upon addition of HCl or NaOH are;

HCI(aq)+CH3COONa(s) ----> CH3COOH(aq)+NaCl(s)

NaOH(aq)+CH3COOH(aq) ----> CH3COONa(s)+H2O(l)

5 0

3 years ago

Where do most carbon monoxide emissions come from?

qwelly [4]

Answer:

The largest anthropogenic source of CO in the United States is vehicle emissions.

Explanation:

4 0

3 years ago

How many moles of lithium oxide will form if 1.68 mol of lithium react?

levacccp [35]

Based on the chemical equation, 4 moles of lithium reacts with 1 mole of oxygen to produce 2 moles of lithium oxide.
First of all you need to find 1 mole of Lithium by diving 1.68 mol by 4 and the answer should be 0.42 mol. To calculate the no. of moles of lithium oxide, you've to multiply 0.42 mol by 2. Hence the answer, 0.84 mol.

3 0

3 years ago

When a drawing made with a black marker gets wet, the marker bleeds and more separates into several colors. What method of separ

aleksandr82 [10.1K]

Answer : (4) Chromatography

Explanation :

Chromatography : It is a separation technique of a mixture by passing it through a medium in which components travels at different rates.

There are many types of chromatography but this is paper chromatography.

Paper chromatography : It is used to separate the colored substances. In paper chromatography, water is the mobile phase and paper is the stationary phase. The mixture of components moves at different speeds through the stationary phase so that they can be separated.

In paper chromatography, several colors can be separated based on their solubility. The more soluble a color is, the more readily it will dissolve in mobile phase and farther it will travel.

5 0

3 years ago

Read 2 more answers

Calculate the percentage of the void space out of the total volume occupied by 1 mole of water molecules. The density of water i

gtnhenbr [62]

Answer:

The percentage of the void space out of the total volume occupied is 93.11%

Explanation:

A mole of water contains 2 atoms of hydrogen and 1 atom of oxygen.

To calculate the volume of a mole of water, we calculate 2 times the volume of the hydrogen atom and 1 times the volume of the oxygen atom

Let's calculate this one after the other.

For the hydrogen, formula for the volume will be

$V_{hydrogen$ = 2 × 4/3 × π × $r_{H}^{3}$

where $r_{H}^{3}$ = 37 pm which is read as 37 picometer (1 picometer = 10^-12 m) = 37 × $10^{-12}$ meters

Volume of the hydrogen = 8/3 × (37 × 10^-12)^3 = 4.05 * 10^-31

we multiply this by the avogadro's number = 6.02 * 10^23

= 4.05 * 10^-31 * 6.02 * 10^23 = 2.6 * 10^-8 m^3

We do same for thr oxygen, but this time we do not multiply the volume of the oxygen by 2 as we have only one atom of oxygen

Volume of oxygen = 4/3 * π * (73 * 10^-12) ^3 * avogadro's number = 9.81 * 10^-7 m^3

adding both volumes together, we have 1.24 * 10^-6 m^3 or simply 1.24 ml ( 0.01 m = 1 ml)

Dividing the molar mass of one mole of water by its density, we can get the volume of 1 mole of water

= (18g/mol)/(1 g/ml) = 18 ml/mol

Now we proceed to calculate the volume of void = Total volume - volume of molecule = 18 - 1.24 = 16.76 ml

Now, the percentage of void = volume of void/total volume * 100%

= 16.76/18 * 100% = 93.11%

7 0

3 years ago