What is the force of gravity between Earth (6.0 × 1024 kilograms) and Venus (4.88 × 1024 kilograms)? The distance between the tw
2 answers:
Solutions
F = Gm₁m₂ /
To solve this given equation we have to multiply variable G by the mass of the Earth ( 5.98 × 1024 kilograms) and the mass of Venus ( 4.88 × 1024 kilograms) , divide by the distance between the planets ( <span>3.8 × 10 ).
</span>5.98 × 1024 = 6123.52 kilograms
= Mass of Earth
4.88 × 1024 = 4997.12 <span>kilograms</span>
= Mass of Venus
<span>3.8 × 10 = 38
</span>= Divide the distance by 38
<span>The value of G is 6.673 × 10-11 newton meter^2 / kilogram
= </span>
F = Gm₁m₂ /
To solve this given equation we have to multiply variable G by the mass of the Earth ( 5.98 × 1024 kilograms) and the mass of Venus ( 4.88 × 1024 kilograms) , divide by the distance between the planets ( <span>3.8 × 10 ).
</span>5.98 × 1024 = 6123.52 kilograms
= Mass of Earth
4.88 × 1024 = 4997.12 <span>kilograms</span>
= Mass of Venus
<span>3.8 × 10 = 38
</span>= Divide the distance by 38
<span>The value of G is 6.673 × 10-11 newton meter^2 / kilogram
= </span>
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9514 1404 393
Answer:
149.04°
Step-by-step explanation:
You must consider the signs of the components of the vector. The value -5+3i will be in the 2nd quadrant of the complex plane.
When you use the single-argument arctan function, it will tell you the angle is -30.96°, a 4th-quadrant angle. (arctan( ) is only capable of giving you 1st- or 4th-quadrant angles.)
You find the 2nd-quadrant angle by adding 180° to this value:
-30.96° +180° = 149.04° = arg(-5+3i)
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The attachments show the calculation using a suitable calculator (1st) and a spreadsheet (2nd). The spreadsheet function ATAN2(x,y) gives the 4-quadrant angle in radians, considering the signs of the two arguments. Here, we converted it to degrees. The calculator can be set to either degrees or radians.
