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Evgen [1.6K]
3 years ago
11

What is the force of gravity between Earth (6.0 × 1024 kilograms) and Venus (4.88 × 1024 kilograms)? The distance between the tw

o planets is about 3.8 × 1010 meters. (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)
Mathematics
2 answers:
Andrej [43]3 years ago
8 0
The formula is F=Gm1m2/d^2. m1=mass of earth m2=mass of venus d=distance between earth nd venus
vodka [1.7K]3 years ago
5 0
Solutions 

F = Gm₁m₂ / r^2 

To solve this given equation we have to multiply variable G by the mass of the Earth ( 5.98 × 1024 kilograms) and the mass of Venus ( 4.88 × 1024 kilograms) , divide by the distance between the planets ( <span>3.8 × 10 ). 

</span>5.98 × 1024 = 6123.52 kilograms
= Mass of Earth 

4.88 × 1024 = 4997.12 <span>kilograms</span>
= Mass of Venus 

<span>3.8 × 10 = 38 
</span>= Divide the distance by 38

 <span>The value of G is 6.673 × 10-11 newton meter^2 / kilogram 

= </span>1.352*10^1^8 N
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This next question I edited a bit.  Your question just says find the four terms.  I'm assuming they meant the first four. I also changed the c to an a.

Find the first four terms of the sequence given by: a_n=n a_{n-1}-3,a_1=2:

a) 2,1,0.-3

You might want to read that second question again because there is errors in the question or things that don't really make sense.  I made my own interpretation of the problem based on my own mathematical experience.

Step-by-step explanation:

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So more terms of the sequence starting at first term 6 is:

6,10,14,18,....

This is an arithmetic sequence.  When thinking of arithmetic sequences you should just really by thinking about equations of lines.

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x  |   y

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1      6

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3     14

4     18

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We also know point slope form of a line is y-y_1=m(x-x_1) where m is the slope and (x_1,y_1) is a point on the line.  You can use any point on the line. I'm going to use the first point (1,6) with my slope=4.

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y=6+4(x-1)    :I added 6 on both sides here.

y=6+4x-4     :I distribute here.

y=4x+2        :This is what I get after combining like terms.

So a_n=y and x=n so you have:

a_n=4n+2

---------------------------------------------------------------------------------------

The first four terms of this sequence will be given by:

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a_1=2 so it is between choice a, c, and d.

a_n=na_{n-1}-3

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a_2=2a_{1}-3

a_2=2(2)-3

a_2=4-3

a_2=1

So we have to go another further the only one that has first two terms 2,1 is choice a.

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