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seropon [69]
3 years ago
5

Which of the following is the area of a quadrilateral with vertices at (-4,2),(1,2),(1,-3) and (-4,-3)

Mathematics
1 answer:
kow [346]3 years ago
3 0

Answer:

The correct option is B.

Step-by-step explanation:

The given vertices are (-4,2),(1,2),(1,-3) and (-4,-3).

Plot these point on a coordinate plate. From the graph it is noticed that the given quadrilateral is a square.

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Use distance formula to find the side length.

AB=\sqrt{(1-(-4))^2+(2-2)^2}=\sqrt{5^2}=5

BC=\sqrt{(1-1)^2+(-3-2)^2}=\sqrt{(25}=5

Since both consecutive sides are equal therefore it is a square.

Area of a square is

A=a^2

Where, a is side length.

The side length of the square is 5. So, area of ABCD is

A=(5)^2

A=25

Therefore the area of quadrilateral is 25 units square. Option B is correct.

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Talia is buying beads to make bracelets. She makes a bracelet with 7 plastic beads and 5 metal beads for $7.25. She makes anothe
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<h2>Plastic Beads = $0.50</h2><h2>Metal Beads = $0.75</h2><h2 />

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m = Metal Beads

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7p + 5m = 7.25

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3 * (7p + 5m = 7.25) = 21p + 15m = 21.75

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<h3><u>p = 0.5</u></h3><h3 />

Substitute the result into one of the original equations.

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Rearrange to find the missing value:

7.25 - (7 * 0.5) = 5m

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5m = 3.75

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<h3><u>m = 0.75</u></h3>
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