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nasty-shy [4]
3 years ago
6

Help me with B please

Mathematics
1 answer:
salantis [7]3 years ago
4 0
Area of each piece of paper is 8\frac{1}{2}\times11=\frac{17}{2}\times11=\frac{187}{2}

Greatest number of possible piece of paper is [1000\div\frac{187}{2}]=[1000\times\frac{2}{187}]=[\frac{2000}{187}]=10
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