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1 answer:

4 0

Area of each piece of paper is $8\frac{1}{2}\times11=\frac{17}{2}\times11=\frac{187}{2}$

Greatest number of possible piece of paper is $[1000\div\frac{187}{2}]=[1000\times\frac{2}{187}]=[\frac{2000}{187}]=10$

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