Explanation:
so as to reduce the force of friction on the hinges and also to make the hinges to move freely
Answer:
K = 1.29eV
Explanation:
In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:
(1)
Δx : uncertainty of position = 2.0pm = 2.0*10^-12m
Δp: uncertainty of momentum = ?
h: Planck's constant = 6.626*10^-34 J.s
You calculate the minimum possible value of Δp from the equation (1):
![\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}](https://tex.z-dn.net/?f=%5CDelta%20p%3D%5Cfrac%7Bh%7D%7B4%5Cpi%20%5CDelta%20x%7D%3D%5Cfrac%7B6.626%2A10%5E%7B-34%7DJ.s%7D%7B4%5Cpi%282.0%2A10%5E%7B-12%7Dm%29%7D%5C%5C%5C%5C%5CDelta%20p%3D2.63%2A10%5E%7B-23%7Dkg.%5Cfrac%7Bm%7D%7Bs%7D)
The minimum kinetic energy is calculated by using the following formula:
(2)
m: mass of the proton = 1.67*10^{-27}kg
![k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B%282.63%2A10%5E%7B-23%7Dkgm%2Fs%29%5E2%7D%7B2%281.67%2A10%5E%7B-27%7Dkg%29%7D%3D2.08%2A10%5E%7B-19%7DJ)
in eV you have:
![2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV](https://tex.z-dn.net/?f=2.08%2A10%5E%7B-19%7DJ%2A%5Cfrac%7B6.242%2A10%5E%7B18%7DeV%7D%7B1J%7D%3D1.29eV)
The kinetic energy of the proton is 1.29eV
Answer:
Out of them, the mantle is the thickest layer, while the crust is the thinnest layer.