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ivanzaharov [21]
3 years ago
13

In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the max

imum centripetal acceleration of a cheetah was measured to be 17 m/s2.What minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?
Physics
1 answer:
geniusboy [140]3 years ago
8 0

Answer:

coefficient of static friction is 1.7329

Explanation:

given data

velocity = 60 mph

acceleration  = 17 m/s²

to find out

coefficient of static friction

solution

we will apply here centripetal force equation

that is

m×v²/r  =  µ × m × g      ..................1

here v²/r is centripetal acceleration and m is mass and  µ  is coefficient static friction so

µ = a / g

µ = 17 / 9.81

µ  = 1.7329

so coefficient of static friction is 1.7329

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Physics Homework MathPhys homie if you see this pls help
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Answer:

1. -8.20 m/s²

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1. Apply Newton's second law to the car in the y direction.

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N = mg

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a = -8.20 m/s²

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6 0
3 years ago
A piston-cylinder device initially contains 1.4 kg saturated liquid water at 200oC. Now heat is transferred to the water until t
postnew [5]

Answer:

Explanation:

Given

mass of saturated liquid water m=1.4\ kg

at 200^{\circ} specific volume is \nu =0.001157\ m^3\kg(From Table A-4,Saturated water Temperature table)

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T_2=370.7^{\circ} C

4 0
3 years ago
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