HELP PLEASE!!! In the diagram, q1 = -6.39*10^-9 C and q2 = +3.22*10^-9 C. What is the electric field at point P? Include a + or
- sign to indicate the direction. 91 92 P 0.150 m ** 0.250 m (Hint: The distance from q1 to P is NOT 0.150 m.) (Remember, E points away from + charges, and toward charges.) (Unit = N/C) HELP PLEASE!!
1 answer:
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The speed is 0.956 m / s.
<u>Explanation</u>:
The kinetic energy is equal to the product of half of an object's mass, and the square of the velocity.
K.E = 1/2 m
where K.E represents the kinetic energy,
m represents the mass,
v represents the velocity.
K.E = 1/2 m
1.10 10^42 = 1/2
3.26
10^31
= (1.10
10^42
2) / (3.26
10^31)
v = 0.956 m / s.