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kozerog [31]
3 years ago
8

two sides of a triangle measure to 20cm and 30cm. Which of the following could be measure by the third side

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0

Answer: With no choices given here, here are a few possibilities.

If it is not a right triangle, the third side could be any number less than 50 cm

If it is a right triangle, the third side could be the hypotenuse, which would be 10√13 or about 36.05 cm.

If 30cm is the hypotenuse, the other side would be 10√5 or about 22.36 cm

Step-by-step explanation: If the two given sides add up to 50, they flatten out to a straight line, equal to the third side, so it is no longer a triangle. The third side must be less than the sum of the other two sides.

We can use the Pythagorean Theorem a² + b² = c² to calculate the lengths of the sides of a right triangle.

For example

20² + 30² = c²

400 + 900 = c²

1300 = c²

√1300 = √(100)(13) = √c²

10√13 = c ≈ 36.05

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Ignoring those who said they weren't sure, there were 297 men asked, and 183 said yes, they had driven a car when they probably
USPshnik [31]

Answer:

z=\frac{0.616-0.5}{\sqrt{\frac{0.5(1-0.5)}{297}}}=3.998  

p_v =2*P(z>3.998)=0.0000639  

With the most common significance levels used \alpha= 0.1, 0.05, 0.01 we see that the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can say that the true proportion is significantly higher than 0.5

Step-by-step explanation:

Information given  

n=297 represent the random sample of male taken

X=183 represent the  men who said yes, they had driven a car when they probably had too much alcohol

\hat p=\frac{183}{297}=0.616 estimated proportion of men who said yes, they had driven a car when they probably had too much alcohol

p_o=0.5 is the value that we want to test

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Hypothesis to test

We need to conduct a hypothesis in order to test the claim that the majority of men in the population (that is, more than half) would say that they had driven a car when they probably had too much alcohol, and the system of hypothesis are:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

After replace we got:

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.616-0.5}{\sqrt{\frac{0.5(1-0.5)}{297}}}=3.998  

Decision

We have a right tailed test so then the p value would be:  

p_v =2*P(z>3.998)=0.0000639  

With the most common significance levels used \alpha= 0.1, 0.05, 0.01 we see that the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can say that the true proportion is significantly higher than 0.5

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3 years ago
What is the reciprocal of -2/3
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3/-2

I Hoped I Helped

<span>ΩΩΩΩΩΩΩΩΩΩ</span>
8 0
3 years ago
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9966 [12]

Answer:

a) 0.70

b) 0.82

Step-by-step explanation:

a)

Let M be the event that student get merit scholarship and A be the event that student get athletic scholarship.

P(M)=0.3

P(A)=0.6

P(M∩A)=0.08

P(not getting merit scholarships)=P(M')=?

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P(not getting merit scholarships)=1-0.3

P(not getting merit scholarships)=0.7

The probability that student not get the merit scholarship is 70%.

b)

P(getting at least one of two scholarships)=P(M or A)=P(M∪A)

P(getting at least one of two scholarships)=P(M)+P(A)-P(M∩A)

P(getting at least one of two scholarships)=0.3+0.6-0.08

P(getting at least one of two scholarships)=0.9-0.08

P(getting at least one of two scholarships)=0.82

The probability that student gets at least one of two scholarships is 82%.

4 0
3 years ago
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lianna [129]
For this case, the first thing to do is to graph the following ordered pairs:
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 Note: see attached image.
 Answer:
 
The function that best represents the ordered pairs is:
 
y = x + 5

5 0
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mote1985 [20]

Answer:

y = -7/3x

y = -10

8 0
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