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Complete the table to investigate dilations of exponential functions.

Zinaida [17]

Answer:

a = 1

b = 3

c = 1

d = 2

e = 6

f = 8

Step-by-step explanation:

Any integer with power as zero = 1

2^x

2^0

= 1

3 * 2^x

3 * 2^0

3 * 1

= 3

2 ^ 3(x)

2 ^ 3(0)

2 ^ 0

= 1

2^1

= 2

3 * 2^x

3 * 2^1

3 * 2

= 6

2 ^ 3(x)

2 ^ 3(1)

2 ^ 3

2 * 2 * 2

= 8

6 0

4 years ago

The value of the surface area (in square centimeters) of the cone is equal to the value of the volume (in cubic centimeters) of

Dovator [93]

Answer:

The height of the cone is 10.9 cm

Step-by-step explanation:

step 1

Find the height of the cone

Applying the Pythagoras Theorem

$12^{2}=5^{2}+h^{2}$

$144=25+h^{2}$

$h^{2}=144-25$

$h^{2}=119$

$h=10.9\ cm$

therefore

The height of the cone is 10.9 cm

6 0

3 years ago

A housekeeper had 4/5 of a spray bottle of a cleaning solution. He used 1/8 of the solution in a day.How much of the bottle did

valina [46]

Answer:

0.1

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Find out the cylinders volume whose height is 3 cm and radius 5cm

Studentka2010 [4]

Volume = πr²h

Volume = π(5)²(3)

Volume = 75π = 235.62 cm³ (nearest hundredth)

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Answer: Volume = 235.62 cm³.
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8 0

3 years ago

Read 2 more answers

Find the IQR (interquartile range).<br> 19, 21, 18, 17, 18, 22,46

yanalaym [24]

Answer:

4.

Step-by-step explanation:

Step 1: <u>Formula.</u>

$IQR=Q3-Q1$

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Step 2: <u>Explain/define.</u>

The interquartile range is the difference between quartile 3 and quartile 1.
Quartile 1 is the median of the upper half of a data set.
Quartile 3 is the median of the lower half of a data set.
The median is the 'middle value.'

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Step 3: <u>Order/arrange.</u>

In order to find the median, you must first put the numbers in numerical order.

19, 21, 18, 17, 18, 22, 46

↓

17, 18, 18, 19, 21, 22, 46

The lower half of the data set, not including the median of the whole data set, is 17, 18, and 18.

The upper half of the data set is 21, 22, and 46.

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Step 4: <u>Solve.</u>

17, 18, 18

21, 22, 36

Next, we find the medians of both sets.

The median of the lower half is 18 (Q1).

The median of the upper half is 22 (Q3).

Lastly, we subtract Q3 from Q1.

$22-18=4.$

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Step 5: <u>Conclude.</u>

I, therefore, believe the interquartile range of this data set is 4.

3 0

3 years ago