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Cloud [144]
4 years ago
11

The sixth term is 22 and the common difference is six what is the fiftieth term

Mathematics
1 answer:
IrinaK [193]4 years ago
7 0
Hey! :)

The general formula for an arithmetic sequence is: a(n) = a + d(n - 1) 
a : first term d : common difference (6) n : number of the term 
In your example, you are told the 6th term is 22. a(6) = a + 6(6 - 1) = 22 a + 30 = 22 a = 22 - 30 a = -8 
So now you have the general formula: a(n) = -8 + 6(n - 1) 
If you like you can simplify it: a(n) = -8 + 6n - 6 a(n) = 6n - 14 
Then you can plug in n = 50: a(50) = 6(50) - 14 = 300 - 14 = 286
So your answer is 286

Hope this helps! :)
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melisa1 [442]

Answer:

B = 781.347

Step-by-step explanation:

Since we already have an equation just plug in terms where needed.

B=17(243)^{\frac{4}{5}}

First, start by multiplying to get rid of the parentheses.  

B=4131^{\frac{4}{5}}

Now get rid of the power.

B = 781.347

Hope this helps with the problem.

5 0
3 years ago
Explain how 50 tens x 4 hundreds = 40 tens x 5 hundreds
Anna007 [38]
50 tens is equal to 500 because if you multiply a number by 10, you just add a 0 behind it.
4 hundreds is literally just 400.
So 500 x 400 = 200,000

40 * 10 = 400
5 * 100 = 500
400 x 500 = 200,000

so both sides are equal to 200,000 and therefore the equation is true.
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Vinil7 [7]
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A=10 B= -2
F(a) =4 F(b)=17
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