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3 years ago

5

What is a prime number

1 answer:

mariarad [96]3 years ago

5 0

Answer:

A prime number is a number whose factors are only 1 and itself.

Step-by-step explanation:

Example:

2 is a prime number because its only factors are 1 and itself (2). 4 is not a prime number because its factors are 1, 2, and 4.

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How many time larger is 5000 to 5

disa [49]

Answer:

1000 times larger.

Step-by-step explanation:

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2 years ago

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Twice a number x, minus 17

LekaFEV [45]

Answer:

2x - 7

Step-by-step explanation:

Twice a number x means x times 2, which can be written as 2x

Minus 17 from 2x

7 0

3 years ago

What is the interval notation for the compound inequality? x≤−5 or x>4

Hoochie [10]

Answer:

$(-\infty, -5] \cup (4,\infty)$

Step-by-step explanation:

The symbol $\cup$ is set notation for UNION--put two sets together into one set.

The first part of the interval notation describes x less than or equal to -5 -- notice the bracket symbol after -5, meaning include -5.

5 0

2 years ago

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago

Please please answer this with the right answer and thanks for your help???<br><br>14 POINTZ!!<br>

professor190 [17]

# 5 the answers is A

4 0

3 years ago

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