If you have
|a|=b, then solve for the variable in euations
a=b and a=-b
for ineqalities, it is much trickier
for
|a|>b, assume a>b and a<-b
for
|a|<b, asssume -b<a<b
This can be mathematically expressed to
250 + X = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825
You produced 825 parts in the middle of the shift.
A local hamburger shop sold a total of 712 burgers on Tuesday
There are 62 more cheeseburgers than hamburgers
let cheeseburers = c
let hamburgers = h
h + 62 = c
c + h = 712
Plug in h + 62 for c
(h + 62) + h = 712
2h + 62 = 712
2h + 62 (-62) = 712 (-62)
2h = 650
2h/2 = 650/2
h = 325
There are 325 hamburgers sold on Tuesday
c = 325 + 62
c = 387
<em>There are 387 chesseburgers sold on tuesday </em>(in case you were wondering)
hope this helps
Answer:
5 Hamburgers = $12.50 4 Chicken sandwiches $8.00( $12.50 + $8.00 = $20.50
Step-by-step explanation:
