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GenaCL600 [577]
3 years ago
12

Gerold invested $118 in an account that pays 6 percent simple interest. how much money will he have at the end of 5 years

Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0
If you would like to know how much money will Gerold have at the end of 5 years, you can calculate this using the following steps:

1 year: $118 + 6% * $118 = 118 + 6/100 * 118 = 118 + 7.08 = $125.08
2 year: $125.08 + 6% * $125.08 = 125.08 + 6/100 * 125.08 = 125.08 + 7.50 = $132.58
3 year: $132.58 + 6% * $132.58 = 132.58 + 6/100 * 132.58 = 132.58 + 7.95 = $140.53
4 year: $140.53 + 6% * $140.53 = 140.53 + 6/100 * 140.53 = 140.53 + 8.43 = $148.96
5 year: $148.96 + 6% * $148.96 = 148.96 + 6/100 * 148.96 = 148.96 + 8.94 = $157.9

The correct result would be $157.9.
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Use the figure below to determine the length of sides b and c. options: b = 5√3, c = 10 b =10, c = 5√3 b = 5√2, c = 10√3 b = 5,
Reil [10]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
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Rusty is 5.75 feet tall and casts a 7 foot shadow find the angle of elevation from the tip of the shadow to the top of Rusty’s h
11Alexandr11 [23.1K]

Answer:

Ф = 39.4 degrees

Step-by-step explanation:

The ratio 5.75 / 7 is the tangent of the angle of elevation.  Using the inverse tangent function on a calculator returns Ф = 39.4 degrees.

5 0
2 years ago
Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.
juin [17]

Answer:

108 cm^2

Step-by-step explanation:

The lateral surface area of a pyramid is given as

LSA= 1/2×perimeter of the base×slant height

base is hexagon with side 3 cm , therefore, perimeter of the base

=6×3=18 cm

slant height = 12 cm

thus, LSA = 1/2×18×12 = 108 cm^2

4 0
3 years ago
Plz show work and solve quick please need help!!!!!
Simora [160]
Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

\sf A=lw

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

\sf A=(56)(27)

\sf A=1512cm^2

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

\sf 82.8-28=54.8\? cm

Calculate the area:

\sf A=\dfrac{1}{2}bh

\sf A=\dfrac{1}{2}(27)(54.8)

\sf A=739.8\?cm^2

We have two of these triangles.

\sf 739.8\times 2=1479.6\? cm^2

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

\sf 81.2-27=54.2\?cm

Now find the area:

\sf A=\dfrac{1}{2}bh

\sf A=\dfrac{1}{2}(56)(54.2)

\sf A=1517.6\? cm^2

We have two of these triangles.

\sf 1517.6\times 2=3035.2\?cm^2

Add all the areas together:

\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}
7 0
3 years ago
Each<br>angles<br>of<br>an equilateral<br>traingle is 60, proove it<br>experimentally<br>​
MArishka [77]

Answer:

True

Step-by-step explanation:

We knwo this is true because a triangle angle theorem is that the sum of the angles in a triangle is equal to 180 degrees.

Since tri = 3 then,

=> 180/3 = 60

Equal = same --> def. of equilateral triangle

Thus, we know it is true that in an equilateral triangle, each angle is 60 degrees

Hope this helps!

5 0
3 years ago
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