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3 years ago

Gerold invested $118 in an account that pays 6 percent simple interest. how much money will he have at the end of 5 years

1 answer:

6 0

If you would like to know how much money will Gerold have at the end of 5 years, you can calculate this using the following steps:

1 year: $118 + 6% * $118 = 118 + 6/100 * 118 = 118 + 7.08 = $125.08
2 year: $125.08 + 6% * $125.08 = 125.08 + 6/100 * 125.08 = 125.08 + 7.50 = $132.58
3 year: $132.58 + 6% * $132.58 = 132.58 + 6/100 * 132.58 = 132.58 + 7.95 = $140.53
4 year: $140.53 + 6% * $140.53 = 140.53 + 6/100 * 140.53 = 140.53 + 8.43 = $148.96
5 year: $148.96 + 6% * $148.96 = 148.96 + 6/100 * 148.96 = 148.96 + 8.94 = $157.9

The correct result would be $157.9.

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Please help! 50 points :) I'll report if you answer just to get points without answering my question -_-.

Kisachek [45]

Answer:

6.4102516109 would be in powers:

6^10

We group numerical factors.

We simplify powers of 10

5 0

3 years ago

Linda gets paid $80 per day. Unfortunately Linda went home sick after working 1/3 of the day on Friday. At her company they don’

Ludmilka [50]

Answer:

26.67

Step-by-step explanation:

Take the total amount per day and multiply by the fraction of the day that she worked

80 *1/3 =26.66666

Rounding to the nearest cent

26.67

7 0

3 years ago

Solve for x<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7Ba%7D%20" id="TexFormula1" title=" \frac{x}{a} " alt=" \fra

NeX [460]

X=a(y/b)
multiply out a on both sides

6 0

3 years ago

Find the general solution of<br><br> dz/dt=5ze^(sint)cost+2e^(sint)cost

gizmo_the_mogwai [7]

Answer:

The general solution of given differential equation is $\frac{1}{5}ln|5z+2|=e^{\sin t}+C$ .

Step-by-step explanation:

The given differential equation is

$\frac{dz}{dt}=5ze^{\sin t}\cos t+2e^{\sin t}\cos t$

Taking out common factors.

$\frac{dz}{dt}=(5z+2)e^{\sin t}\cos t$

Using variable separable method, we get

$\frac{dz}{5z+2}=e^{\sin t}\cos t dt$

Integrate both sides.

$\int\frac{dz}{5z+2}=\int e^{\sin t}\cos t dt$

$I_1=I_2$ .... (1)

First solve LHS,

$I_1=\int\frac{dz}{5z+2}$

Substitute $5z+2=u$

$5\frac{dz}{du}=1$

$dz=\frac{1}{5}du$

$I_1=\frac{1}{5}\int\frac{du}{u}$

$I_1=\frac{1}{5}ln|u|+C_1$

$I_1=\frac{1}{5}ln|5z+2|+C_1$

Now, solve RHS,

$I_2=\int e^{\sin t}\cos t dt$

Substitute $\sin t=v$ ,

$\cos t\frac{dt}{dv}=1$

$\cos tdt=dv$

$I_2=\int e^{v}dv$

$I_2=e^{v}+C_2$

$I_2=e^{\sin t}+C_2$

Subtitle the values of I₁ and I₂ in equation (1).

$\frac{1}{5}ln|5z+2|+C_1=e^{\sin t}+C_2$

$\frac{1}{5}ln|5z+2|=e^{\sin t}+C_2-C_1$

$\frac{1}{5}ln|5z+2|=e^{\sin t}+C$

Therefore the general solution of given differential equation is $\frac{1}{5}ln|5z+2|=e^{\sin t}+C$ .

4 0

3 years ago

a spinner has three unequal sections: red, yellow, and blue. the table shows the results of nolan’s spins (red:10, yellow:14, bl

zubka84 [21]

A spinner has three unequal sections.

Red = 10

Yellow = 14

Blue = 6

$Total\: sections=Red+Yellow+Blue=10+14+6=30$

We are asked to find the experimental probability of landing on yellow.

Recall that the experimental probability is given by

$P=\frac{\text{number of desired outcomes}}{\text{total number of possible outcomes}}$

In this case, the number of desired outcomes are

Yellow = 14

The total number of possible outcomes is

Total sections = 30

$P=\frac{14}{30}=\frac{7}{15}$

Therefore, the experimental probability of landing on yellow is 7/15

7 0

1 year ago