(20 POINTS AND BRAINLIEST!!!) Need help with algebra 1 questions.

A sports shop has 30 employees. 70% of the employees work part-time. How many part-time employees does the sports shop have?

noname [10]

Answer:

21

Step-by-step explanation:

all you have to do is get 70% of 30

70% of 30 is 21

4 0

1 year ago

Read 2 more answers

When someone buys a ticket for an airline flight, there is a 0.098 probability that the person will not show up for the flight.

DedPeter [7]

Answer:

Step-by-step explanation:

Probability that a person will not show up is,

P(person not show up)=0.098.

Probability that they will show up is

1-0.098=0.902

P(person will show up)=0.902

Jet passenger seat=18.

a. But is it wise to book 20 passenger seat

If the flight attendant book 20.

We want to know the probability that the two person will not show up.

The probability that the 2 person will not show up out of the 20 is given as

Using binomial distribution

Check attachment for formulas.

P(2 not showing up) =

20C2 • 0.098² • 0.902^20=0.2319

Which is 23.19% that the 2 person will not show up.

b. But is it wise to book 24 passengers for 22 jet seat.

The probability that the 2 will not show up out of the 24 is given as

Using binomial distribution

P(2 not showing up) =

24C2 • 0.098²• 0.902²²=0.2741

Which is 27.41% that the four person will not show up.

c. Probability of no enough seat

For 20 passengers and 18seats on jet

1-0.2319=0.7631.

For 24 passengers and 20 seats on jet

1-27.41=0.7259.

Then, It is not a wise decision because the probability that there are not enough seats on the jet is 0.7259 (72.59%). So, overbooking is an unlikely event.

5 0

2 years ago

Use the given information to find the minimum sample size required to estimate an unknown population mean μ.

larisa86 [58]

Answer:

The number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.

Step-by-step explanation:

The (1 - α) % confidence interval for population mean is:

$CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

The margin of error for this interval is:

$MOE= z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

The information provided is:

σ = $569

MOE = $140

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the sample size required as follows:

$MOE= z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}$

$=[\frac{1.96\times 569}{140}]^{2}\\\\=63.457156\\\\\approx 64$

Thus, the number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.

4 0

3 years ago

Complete the congruence statement

Dvinal [7]

Angle Y equals Angle S

8 0

3 years ago

I need to find the measure of each angle. I don't know where or how to start?

kirill115 [55]

Answer:

40°

Step-by-step explanation:

Every triangle adds up to 180°

So to get the angle of the triangle we already have two values of:

$180 - 79 - 52 = 50$

Then since it's at a 90° angle we can subtract 50 to get:

40° as the other part of the right angle.

And applying the 180 rule again:

$180 - 100 - 40 = 40$

7 0

3 years ago