Answer: The point where the two graphed lines cross is the solution to the system of equations. (1, -1)
Step-by-step explanation:
The second equation is already in slope-intercept form y = x - 2
the slope is +1 (invisible coefficient of x) and the y-intercept is -2
y = mx +b
"m" is the slope (the coefficient of x) Positive slopes go up from left to right
"b" is the y-intercept, where the graphed line crosses the x-axis
Rewrite the first equation in slope-intercept form.
6x + y = 5 subtract 6x from both sides
<em>-6x</em> + 6x +y = -<em>6x</em> + 5 .( left side 6x + 6x =0 so "cancel")
y = -6x + 5
Then you know the slope and the intercepts
b = 5 so start with a point at +5 in the y-axis
m = -6 so from there go down 6 and over to the right 1 square and plot another point. Draw a straight line through the two points.
The point where the two graphed lines cross is the solution to the system of equations.
Your graph should look like the screenshot below.
Answer:
$121.51
Step-by-step explanation:
At 18.7%, the monthly multiplier is 1+.187/12, so for the year, James' balance is multiplied by (1+.187/12)^12 ≈ 1.2038899
At 12.5%, the monthly multiplier is 1+.125/12, so for the year, James' balance is multiplied by (1+.125/12)^12 ≈ 1.1324161
The difference in these multipliers is ...
1.2038899 -1.13241605 = 0.0714739
so James' savings is ...
$1700 × 0.0714739 ≈ $121.51
Answer:
well bcs we cool so appreciated <3 periodTH lolz
Step-by-step explanation:
Answer:
The last one
Step-by-step explanation:
when you are dividing an equation with exponents, you subtract the exponents from each other.
For example, in your problem you have d^4 and d^2 (notice that they have the same base) you subtract the exponents to get d^2
** even if the bases are numbers, you DONT touch the base, just the exponents ( ex.: 5^4 ÷ 5^3 = 5^1)
Do this w/ the rest of the exponents.
d^4 ÷ d^2 = d^2
e^3÷e^2= e
f^5÷f= f^4
** although f looks like it doesn't have an exponent, it has an invisible one
And w/ the power of deduction, you should get -2/3 d^2ef^4
Answer:
pizza: $4, coke: $3, chips: $2
Step-by-step explanation:
Lets make the price of a pizza=p a coke= k and a bag of chips=c
then we have the following equations
p+k+c=9
p+2k=10
2p+2c=12
Because p is common in all the equations we shall make it the subject of each equation.
p=9-(k+c)...........i
p=10-2k..............ii
p=6-c...................iii
We then equate i and iii
9-(k+c)=6-c
9-k-c=6-c
putting like terms together we get:
9-6=-c+c+k
1 coke, k=$3
replacing this value in equation ii
we get p=10-2(3)
p=10-6= 4
1 pizza, p=$4
replacing this value in equation iii
4=6-c
c=6-4
=2
a bag of chips, c=$2
Thus, a pizza, a coke and a bag of chips= pizza: $4, coke: $3, chips: $2
