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nadezda [96]
3 years ago
10

Point A is the incenter of triangle DEF. Point A is the incenter of triangle D E F. Lines are drawn from the points of the trian

gle to point A. Lines are drawn from point A to the sides of the triangle to form right angles and line segments A X, A Y, and A Z. Which must be true? Select three options Point A is the center of the circle that passes through points D, E, and F. Point A is the center of the circle that passes through points X, Y, and Z. Line segment Z A is-congruent-to line segment Y A Line segment E A is-congruent-to line segment F A Line segment A X is-congruent-to line segment A Y
Mathematics
2 answers:
expeople1 [14]3 years ago
8 0

Answer:

B C E

Step-by-step explanation:

puteri [66]3 years ago
4 0

Answer:

The answers are B, C, E

Step-by-step explanation:

Just took it on edge and got them right :)

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Answer this question thanks:)
Viefleur [7K]

First multiply 2 to both sides to isolate q. Since 2 is being divided by q, multiplication (the opposite of division) will cancel 2 out (in this case it will make 2 one) from the left side and bring it over to the right side.

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q < 4

For the graph will you have a empty or colored in circle?

If the symbol is ≥ or ≤ then the circle will be colored in. This represents that the number the circle is on is included.

If the symbol is > or < then the circle will be empty. This represents that the number the circle is on is NOT included.

Which direction will the ray go?

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In this case your inequality is:

q < 4

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Which quadrant would (0,-7) , (0,0) , (8,0)
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help 112. if k is a positive integer, then for every value of k, the sum of the k smallest distinct odd positive integers is equ
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Hello,

\sum_{i=0}^{k-1}\ (2*i+1)=2*\sum_{i=0}^{k-1}\ i +\sum_{i=0}^{k-1}\ 1\\&#10;&#10;= \dfrac{k*(k-1)}{2} +k=k^2-k+k=k^2

In details:

s= 1             +3            +5+7+9+....    +2(k-2)+1      +2(k-1)+1
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Answer J
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Triangle RST is shown below
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Answer:

32

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