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nadezda [96]
2 years ago
10

Point A is the incenter of triangle DEF. Point A is the incenter of triangle D E F. Lines are drawn from the points of the trian

gle to point A. Lines are drawn from point A to the sides of the triangle to form right angles and line segments A X, A Y, and A Z. Which must be true? Select three options Point A is the center of the circle that passes through points D, E, and F. Point A is the center of the circle that passes through points X, Y, and Z. Line segment Z A is-congruent-to line segment Y A Line segment E A is-congruent-to line segment F A Line segment A X is-congruent-to line segment A Y
Mathematics
2 answers:
expeople1 [14]2 years ago
8 0

Answer:

B C E

Step-by-step explanation:

puteri [66]2 years ago
4 0

Answer:

The answers are B, C, E

Step-by-step explanation:

Just took it on edge and got them right :)

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Which point best represents V26 on the number line below? ​
LiRa [457]

Answer:

Th answer is C u got it right

Step-by-step explanation:

7 0
3 years ago
Kevin is 3 years older than Daniel. Two years ago, Kevin was 4 times as old as Daniel.
goldfiish [28.3K]

Answer:

B is the correct answer

Kevin is K

Daniel is D

Now: K

K = D + 3

3 years ago:

K - 2 = 4(d - 2)

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6 0
3 years ago
Read 2 more answers
The coordinate plane below represents a city. Points A through F are schools in the city.
Usimov [2.4K]
Part A. The technique on how to find the equation that only applies to point D and E, is to create a line or curve that only includes two of these points. In this case, I created a random parabola that isolates points C and F from the rest of the points. First, we have to find the equation of the parabola through its general forms:

(x - h)² = +/-4a(y-k)      or    (y - k)² = +/-4a(x - h)

For parabolas drawn like that in the picture, the general form is (x - h)² = +4a(y-k), where the vertex is (h,k) and a is the distance from the vertex to the focus. From the picture, the vertex is at (0,3). Then, we use point D(-2,4) to determine a:

(-2 - 0)² = +4a(4 - 3)
4a = 4

So, the equation of the parabola is:

x² = 4(y - 3)
x² = 4y - 12

Part B. Point D was already verified above. Now for point E(2,4)
x² = 4y - 12
2² ? 4(4) - 12
4 ? 4
4 = 4

Part C. For y < 7x − 4, ignore the equality symbol first and graph the line. Assign random values of x, then you get corresponding values of y. Plot them as shown in the second picture. The line is shown in red. Next, test the equation by choosing a random point. Let's choose the purple point at (4,3).

3 ? 7(4) − 4
3 ? 24
3 < 24

Thus, it applies to the purple point, and all the other areas to that area. The shaded region are all solutions of the inequality. So, Erica is only interested in points E, C and F. 

5 0
3 years ago
In algebra how do i convert y-7=-2/3(x+1) into standard form and what would it be?
Art [367]

Answer:

C

Step-by-step explanation:

Where, if at all possible,

A

,

B

, and

C

are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

8 0
3 years ago
What is the slope?
ANTONII [103]

Answer:

1/3

Steps:

The line rose 10 values (up) and went 30 values higher (to the right), so you divide 10/30 and end up with 1/3

Step-by-step explanation:

6 0
3 years ago
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