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lara31 [8.8K]
3 years ago
15

Nita wants to buy a new keyboard for her computer. She will buy the keyboard when it is on sale for under $50 Write an inequalit

y that describes k, the price in dollars at which Nita will buy the keyboard
Mathematics
2 answers:
gtnhenbr [62]3 years ago
8 0

Answer:

0 ≤ k ≤ 50

Step-by-step explanation:

Here k represents the price of the keyboard ( in dollars ),

Given,

Nita will buy the keyboard,

If the price of the keyboard is under $ 50,

That is,  k \leq 50

Also, the price can not be negative,

⇒ 0 \leq k

Hence, the required inequality is,

0 \leq k \leq 50

adoni [48]3 years ago
3 0

<u><em>This would be k < 50.</em></u>

This inequality states that k, the price at which Nita wants to buy the new keyboard, is less than 50 dollars.

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Gemiola [76]
Your mom can explain ok stop asking
8 0
2 years ago
Suppose that f(5) = 3, f '(5) = 6, g(5) = −5, and g'(5) = 2. Find the following values. (a) (fg)'(5) (b) f g '(5) (c) g f '(5)
baherus [9]

Answer: a) -24

              b) -\frac{36}{25}

              c) 4

Step-by-step explanation:

a) To determine the value of (fg)', use the product rule of derivative, i.e.:

(fg)'(x) = f'(x)g(x) + f(x)g'(x)

(fg)'(5) = f'(5)g(5) + f(5)g'(5)

(fg)'(5) = 6(-5) + 3(2)

(fg)'(5) = -24

b) The value is given by the use of the quotient rule of derivative:

(\frac{f}{g})'(x)=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}

(\frac{f}{g})' (5)=\frac{f'(5)g(5)-f(5)g'(5)}{[g(5)]^2}

(\frac{f}{g})'(5)=\frac{6(-5)-3(2)}{(-5)^{2}}

(\frac{f}{g})'(5)=\frac{-36}{25}

c) (\frac{g}{f})'(5)=\frac{g'(5)f(5)-g(5)f'(5)}{[f(5)]^{2}}

(\frac{g}{f})'(5)=\frac{2(3)-(-5)(6)}{3^{2}}

(\frac{g}{f})'(5)=\frac{36}{9}

(\frac{g}{f})'(5)=4

7 0
2 years ago
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sleet_krkn [62]

Answer:

1.5 acres per hours

Step-by-step explanation:

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8 0
2 years ago
Four (4) fair dice are rolled. what is the probability that the total is 21
liberstina [14]
Short Answer 5/216
Comment
The question really is, how many different types of throws with 4 dice will give 21? You can count them

Pattern 1
6663 

Pattern 2
5556

Pattern 3 [ The hard one]
6654

Patterns 1 and 2 give 4 each.
6 6 6 3
6 6 3 6
6 3 6 6
3 6 6 6

5553 will do the same thing

Both can be found by (4/1) as a combination. 

Now for 6654 That gives 12

6 6 5 4
6 6 4 5
6 5 4 6
6 5 6 4
6 4 5 6
6 4 6 5
5 6 4 6
5 6 6 4
5 4 6 6
4 5 6 6
4 6 5 6
4 6 6 5

That should total 12 
The total number of ways of getting 21 with this pattern is 12

Total successes
12 + 4 + 4 = 30

What is the total number of ways you can throw 4 dice?
Total = 6 * 6 * 6 * 6 = 1296

What is the probability of success?
30 / 1296 = 5 / 216
4 0
3 years ago
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Vladimir79 [104]

Answer:

first find the value of x

4 0
2 years ago
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