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icang [17]
3 years ago
13

Solve 6x^2 - 12x + 24 = 0 by completing the square

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer: \quad x=1+\sqrt{3}i,\:x=1-\sqrt{3}i

Step-by-step explanation: x_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:6\cdot \:24}}{2\cdot \:6}

  • x_{1,\:2}=\frac{-\left(-12\right)\pm \:12\sqrt{3}i}{2\cdot \:6}
  • x_1=\frac{-\left(-12\right)+12\sqrt{3}i}{2\cdot \:6},\:x_2=\frac{-\left(-12\right)-12\sqrt{3}i}{2\cdot \:6}
  • x=1+\sqrt{3}i,\:x=1-\sqrt{3}i

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