Solve 6x^2 - 12x + 24 = 0 by completing the square

Mathematics

1 answer:

IrinaVladis [17]2 years ago

4 0

Answer: $\quad x=1+\sqrt{3}i,\:x=1-\sqrt{3}i$

Step-by-step explanation: $x_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:6\cdot \:24}}{2\cdot \:6}$

$x_{1,\:2}=\frac{-\left(-12\right)\pm \:12\sqrt{3}i}{2\cdot \:6}$

$x_1=\frac{-\left(-12\right)+12\sqrt{3}i}{2\cdot \:6},\:x_2=\frac{-\left(-12\right)-12\sqrt{3}i}{2\cdot \:6}$

$x=1+\sqrt{3}i,\:x=1-\sqrt{3}i$

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