Answer:
6 combinations
Step-by-step explanation:
Let
x----> the number of adult tickets
y---> the number of a child tickets
we know that
5x+3y=100 ----> linear equation that represent the situation
y=-(5/3)x+(100/3)
The maximum number of adult tickets is 20 (20*$5=$100)
The maximum number of a child tickets is 33 (33*$3=$99)
Construct a table for different values of x and find the values of y
The possible combinations will be pairs of whole numbers
see the attached table
The solution is 6 combinations
